The range of the raising operator is complementary to the kernel of the lowering operator #
Let t : IsSl2Triple h e f be an sl₂ triple in a Lie algebra L over a field K of
characteristic zero, and let M be a finite-dimensional L-module. This file proves the
decomposition
M = e • M ⊕ ker f.
The kernel of f consists of the lowest weight vectors. In the decomposition of M into
irreducible V(n)s, each summand contributes one lowest weight line, and the rest of the summand
is the image of the raising operator. The proof here does not use that decomposition, a splitting
field or the diagonalizability of h. It works over any field of characteristic zero.
For the adjoint module this is the direct sum L = [L, e] ⊕ ker (ad f). The first summand is the
image of the differential of the orbit map g ↦ Ad g e of a group with Lie algebra L. The second
is the direction of the affine subspace e + ker (ad f), the Slodowy slice at e. So the
decomposition is the linear-algebraic content of the transversality of the slice to the adjoint
orbit of e. A dimension count also gives dim ker (ad e) = dim ker (ad f): the direction of the
slice has the dimension of the centralizer of e.
The argument #
Write E, F, H for the operators by which e, f, h act. Both E and F are nilpotent.
Disjointness of range E and ker F is proved by descending induction on k ≥ 1: no nonzero
vector of range (E ^ k) is killed by F. For large k the range is zero. For the step, let
v = E ^ (n + 1) w with F v = 0. The commutation formula for F past E ^ (n + 1) shows that
H v - (n + 2) • v lies in range (E ^ (n + 2)). It is also killed by F, so it vanishes by the
induction hypothesis. Then v is a vector of ker F on which H acts by n + 2. The
commutation formula gives F (E ^ (j + 1) v) = -(j + 1) (n + 2 + j) • E ^ j v, so E ^ j v = 0
forces v = 0 by induction on j, and E is nilpotent. Hence v = 0.
The same statement for (-h, f, e) gives that range F and ker E are disjoint. In finite
dimension the two disjointness statements together with rank-nullity force
dim ker E = dim ker F. Hence range E and ker F have complementary dimensions.
Main results #
TauCeti.Sl2.disjoint_range_ker: for operators with nilpotentEsatisfying thesl₂relations withF,range Eandker Fare disjoint. No finiteness is assumed.IsSl2Triple.isNilpotent_toEnd_eandIsSl2Triple.isNilpotent_toEnd_f: in a finite-dimensional module,eandfact nilpotently.IsSl2Triple.isCompl_range_toEnd_e_ker_toEnd_f: the decompositionM = e • M ⊕ ker f.IsSl2Triple.finrank_ker_toEnd_e_eq_finrank_ker_toEnd_f: the highest and lowest weight vectors span subspaces of the same dimension.IsSl2Triple.isCompl_range_ad_e_ker_ad_fandIsSl2Triple.finrank_ker_ad_e_eq_finrank_ker_ad_f: the adjoint forms.
References #
- P. Slodowy, Simple Singularities and Simple Algebraic Groups, Lecture Notes in Mathematics
815, Springer, 1980, Chapter 7, for the slice
e + ker (ad f)and its transversality. - D. H. Collingwood and W. M. McGovern, Nilpotent Orbits in Semisimple Lie Algebras, Van
Nostrand Reinhold, 1993, Chapter 3, for the
sl₂theory of nilpotent elements.
Let E be a nilpotent operator satisfying the sl₂ relations with F and H. Then no nonzero
vector in the range of E is killed by F. No finiteness is needed.
The raising element of an sl₂ triple acts nilpotently on a finite-dimensional module over a
field of characteristic zero.
The lowering element of an sl₂ triple acts nilpotently on a finite-dimensional module over a
field of characteristic zero.
The kernels of the raising and lowering operators of an sl₂ triple on a finite-dimensional
module have the same dimension. These are the spaces of highest and of lowest weight vectors.
The sl₂ decomposition M = e • M ⊕ ker f. For an sl₂ triple (h, e, f) acting on a
finite-dimensional module over a field of characteristic zero, the range of the raising operator
and the kernel of the lowering operator are complementary.
The transverse decomposition L = [L, e] ⊕ ker (ad f). For an sl₂ triple (h, e, f) in a
finite-dimensional Lie algebra over a field of characteristic zero, the range of ad e and the
kernel of ad f are complementary.
The centralizers of the raising and lowering elements of an sl₂ triple in a
finite-dimensional Lie algebra over a field of characteristic zero have the same dimension.