The multiplier ring of a submodule of an algebra #
Let B be a commutative R-algebra and M an R-submodule of B. The multiplier ring
B₀ = {b ∈ B | b M ⊆ M} of the underlying additive subgroup of M
(AddSubgroup.multiplierRing) is a subring of B containing the image of R. This file
compares the R-submodule I • M of B coming from an ideal I of R with the extension of
I to B₀. The submodule I • M lies in B₀ only under a hypothesis such as
I • (M * M) ≤ M (see Submodule.smul_subset_multiplierRing). These comparisons are how a
lattice in a finite algebra over a Huber ring yields a pair of definition.
Main results #
Submodule.toMultiplierRing: the structure mapR → B₀.Submodule.smul_subset_multiplierRing: ifIcarriesM * MintoM, thenI • M ⊆ B₀.Submodule.coe_map_pow_subset: if1 ∈ M, the powers of the extensionJ = I B₀satisfyJⁿ ⊆ Iⁿ • M.Submodule.smul_subset_coe_map_pow: ifIʲ • M ⊆ B₀, thenI^(n + j) • M ⊆ Jⁿ.Submodule.isIntegral_of_mem_multiplierRing: ifMis finitely generated and contains1, every element ofB₀is integral overR.
If an ideal I carries M * M into M, then I • M lies in the multiplier ring of M.
The powers of the extension J = I B₀ of an ideal I of R to the multiplier ring lie in
Iⁿ • M when 1 ∈ M.
If Iʲ • M lies in the multiplier ring, then I^(n + j) • M lies in the n-th power of the
extension J = I B₀ of I to the multiplier ring.
The multiplier ring of a finitely generated submodule containing 1 is integral. If M
is a finitely generated R-submodule of B with 1 ∈ M, every b ∈ B with b M ⊆ M is
integral over R: by Cayley–Hamilton, multiplication by b on M satisfies a monic polynomial,
and evaluating at 1 shows that b satisfies it too.