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TauCeti.Algebra.Polynomial.Cubic.TripleRoot

Monic cubics with a triple root #

A monic cubic X³ + b X² + c X + d is the cube (X - ρ)³ exactly when b = -3ρ, c = 3ρ² and d = -ρ³. Over a perfect field the existence of such a ρ can be read off the coefficients without naming it: it holds exactly when

b² = 3 c, c² = 3 b d, b c = 9 d,

that is, when the quadratic covariant (b² - 3c) x² + (bc - 9d) x y + (c² - 3bd) y² of the binary cubic form x³ + b x² y + c x y² + d y³ vanishes; away from characteristic 2 this covariant is -1/4 times the Hessian of the form. The criterion holds in every characteristic. Away from characteristic 3 the root is ρ = -b / 3. In characteristic 3 the conditions say b = c = 0, and the root is a cube root of -d, which exists because the field is perfect. Over the imperfect field 𝔽₃(s) the cubic X³ - s satisfies the conditions but is not the cube of a linear polynomial.

This is the triple-root test of Tate's algorithm (Steps 6 to 8), applied to the residue cubic of a Weierstrass equation over a discrete valuation ring.

Main results #

A monic cubic X³ + b X² + c X + d over a commutative ring is the cube (X - ρ)³ exactly when b = -3ρ, c = 3ρ² and d = -ρ³.

The triple-root test for a monic cubic. Over a perfect field k, the cubic X³ + b X² + c X + d is (X - ρ)³ for some ρ ∈ k exactly when b² = 3c, c² = 3bd and bc = 9d. Perfectness is needed only in characteristic 3, where the conditions reduce to b = c = 0 and ρ is a cube root of -d.