Inverting one component of a unit #
An idempotent e of a commutative ring R splits it as R ≅ e R × (1 - e) R, and so splits
each unit u into its e-component e u and its (1 - e)-component (1 - e) u. Inverting the
first component and keeping the second is the automorphism
u ↦ e u⁻¹ + (1 - e) u
of the unit group Rˣ, written here without reference to the product decomposition: since
e² = e and e (1 - e) = 0, products of elements of the form e x + (1 - e) y are computed
componentwise.
The automorphism is an involution. At e = 0 it is the identity and at e = 1 it is inversion.
For the idempotent of ZMod N attached to an exact divisor Q of N it is the automorphism of
(ZMod N)ˣ inverting the residue modulo Q and fixing the residue modulo N / Q, through which
the Atkin–Lehner operator W_Q shifts the nebentypus of a modular form.
Main definitions #
IsIdempotentElem.unitsInvPart: the automorphismu ↦ e u⁻¹ + (1 - e) uofRˣ.
Main results #
IsIdempotentElem.mul_unitsInvPart,IsIdempotentElem.one_sub_mul_unitsInvPart: its two components aree u⁻¹and(1 - e) u.IsIdempotentElem.unitsInvPart_symm: it is an involution.IsIdempotentElem.unitsInvPart_zero,IsIdempotentElem.unitsInvPart_one: ate = 0ande = 1it is the identity and inversion.
Inverting the e-component of a unit: for an idempotent e of a commutative ring R,
the automorphism u ↦ e u⁻¹ + (1 - e) u of Rˣ. Under R ≅ e R × (1 - e) R it inverts the first
component and fixes the second. It is its own inverse (unitsInvPart_symm).
Equations
- One or more equations did not get rendered due to their size.
Instances For
The value of unitsInvPart at a unit u is e u⁻¹ + (1 - e) u.
unitsInvPart is an involution: it is its own inverse.
unitsInvPart is an involution, applied twice to a unit.
The e-component of unitsInvPart u is the e-component of u⁻¹.
The (1 - e)-component of unitsInvPart u is the (1 - e)-component of u.
At the idempotent 0 nothing is inverted: unitsInvPart is the identity.
At the idempotent 1 everything is inverted: unitsInvPart is inversion.