Points with singular reduction at a nonsplit node of even order #
Let v be a valuation on a field F, with valuation ring O, maximal ideal 𝔪 and residue field
k, and let W be an elliptic curve over F with an integral model W_O over O whose reduction
is a node at the origin with no rational tangent direction: a₃, a₄, a₆ ∈ 𝔪 and the tangent
quadratic T² + a₁ T − a₂ has no root in k. The points with nonsingular reduction form the
subgroup E₀(F) of W(F) (WeierstrassCurve.Affine.nonsingularReduction), whose index divides
2 (WeierstrassCurve.Affine.index_nonsingularReduction_dvd_two_of_tangentQuadratic_no_roots).
For a discrete valuation, on a minimal equation, this is nonsplit multiplicative reduction of type
Iₙ with n = ord(Δ), and Tate's algorithm reports the local index c_v = gcd(2, n)
(Silverman, Advanced Topics, IV.9, Table 4.1). When n is odd every point has nonsingular
reduction (WeierstrassCurve.Affine.nonsingularReduction_eq_top_of_not_splits). This file proves
the even case: when Δ is a unit times a square, O is Henselian and k is finite, some point
has singular reduction, so [E(F) : E₀(F)] = 2.
The equation-level construction in Affine/Henselian.lean proceeds in three steps over O
(WeierstrassCurve.exists_equation_mem_maximalIdeal_of_tangentQuadratic_no_roots).
- Centring. The singular point of the reduction lifts to a critical point
(r, t) ∈ 𝔪²of the Weierstrass polynomial, and translating it to the origin makesa₃ = a₄ = 0(WeierstrassCurve.exists_translate_a₃_eq_zero_and_a₄_eq_zero). On the centred equationy² + a₁ x y = x³ + a₂ x² + a₆one hasΔ = −a₆ (b₂³ + 432 a₆), soa₆andΔdiffer by a unit. - The residue conic. Write
Δas a unit timesz², so thata₆ = z² AwithAa unit. Along(x, y) = (z X, z Y)the centred equation divided byz²isY² + a₁ X Y − a₂ X² − z X³ = A, whose reduction is the conicY² + a₁ X Y − a₂ X² = A. Its quadratic part is the norm form of the quadratic extensionk[T]/(T² − a₁ T − a₂)ofk, and over a finite field the norm is surjective (FiniteField.norm_surjective), so the conic has a point. - Lifting. The residue conic is smooth, since the discriminant
b₂of its quadratic part is a unit, so one of the partial derivatives is a unit at the point, and Hensel's lemma in that variable lifts it to a solution(X, Y)overO. The solution(z X, z Y)of the centred equation has both coordinates in𝔪, and so does the corresponding point ofW, which therefore has singular reduction.
The finiteness of k is used only to find a point on the residue conic, which over a general
residue field need not exist.
Main results #
WeierstrassCurve.exists_equation_mem_maximalIdeal_of_tangentQuadratic_no_roots: over a Henselian local ring with finite residue field, an equation whose reduction is a nonsplit node at the origin, withΔa unit times a square, has a solution in𝔪 × 𝔪. This is a converse ofWeierstrassCurve.exists_associated_sq_Δ_of_isSingular.WeierstrassCurve.Affine.exists_notMem_nonsingularReduction_of_tangentQuadratic_no_roots: at a nonsplit node withΔa unit times a square, over a Henselian valuation ring with finite residue field, some point has singular reduction.WeierstrassCurve.Affine.index_nonsingularReduction_eq_two_of_tangentQuadratic_no_roots: in the same situation,[E(F) : E₀(F)] = 2.Affine.index_nonsingularReduction_eq_two_of_isTateTerminal_I_of_tangentQuadratic_no_roots: when Tate's algorithm stops with the symbolI₂ₘand the tangent quadratic has no root, that is at nonsplit multiplicative reduction of even type,[E(F) : E₀(F)] = 2.
References #
- J. Silverman, The Arithmetic of Elliptic Curves, VII.6.
- J. H. Silverman, Advanced Topics in the Arithmetic of Elliptic Curves, GTM 151, IV.9.
- J. Tate, Algorithm for determining the type of a singular fibre in an elliptic pencil, in Modular Functions of One Variable IV, LNM 476 (1975), 33–52.
At a nonsplit node with Δ a unit times a square, some point has singular reduction, when
the valuation ring is Henselian, for instance complete, and its residue field is finite. Here the
reduction of the integral model is singular at the origin, a₃, a₄, a₆ ∈ 𝔪, and its tangent
quadratic T² + a₁ T − a₂ has no root in the residue field. For a discrete valuation, on a minimal
equation, this is nonsplit multiplicative reduction of type Iₙ with n even.
At a nonsplit node with Δ a unit times a square, [E(F) : E₀(F)] = 2, when the valuation
ring is Henselian, for instance complete, and its residue field is finite. Here the reduction of
the integral model is singular at the origin, a₃, a₄, a₆ ∈ 𝔪, and its tangent quadratic
T² + a₁ T − a₂ has no root in the residue field. For a discrete valuation, on a minimal equation,
this is nonsplit multiplicative reduction of type Iₙ with n even, where Tate's algorithm reports
the local index 2.
At nonsplit multiplicative reduction of even type I₂ₘ, [E(F) : E₀(F)] = 2, when the
valuation ring is Henselian, for instance complete, and its residue field is finite. This is the
local index c_v = 2 that Tate's algorithm reports there. Here ϖ generates the maximal ideal of
the valuation ring, Tate's algorithm, run on the integral model with uniformiser ϖ, stops with
the symbol I₂ₘ (ϖ ∣ a₃, ϖ ∣ a₄, ϖ ∣ a₆, ϖ ∤ b₂ and ϖ²ᵐ ∥ Δ), and the tangent quadratic
T² + a₁ T − a₂ has no root in the residue field.