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TauCeti.Analysis.CompletelyMonotone.Bernstein.Div

A Bernstein function divided by its parameter is completely monotone #

If f is a Bernstein function, then t ↦ f(t) / t is completely monotone on (0, ∞). This is one of the standard correspondences between Bernstein and completely monotone functions, next to t ↦ e^{-x f(t)} (TauCeti.IsBernsteinFunction.isContinuousCompletelyMonotoneOnIoi_exp_neg_mul) and the primitive of a completely monotone function (TauCeti.IsCompletelyMonotoneOnIoi.isBernsteinFunction_integral). For a complete Bernstein function the quotient is even a Stieltjes function (TauCeti.IsCompleteBernsteinFunction.isStieltjesFunction_div); for a general Bernstein function complete monotonicity is the most one can say.

For a Bernstein function with f(0) > 0, continuity at zero makes the quotient unbounded near the origin. Continuity of f at 0 is not needed for the general theorem, only its nonnegativity and differentiability on (0, ∞) and the complete monotonicity of f' there, so the theorem is stated under exactly those hypotheses and specialized to Bernstein functions afterwards.

The sign of dⁿ/dtⁿ (f(t) / t) is that of (-1)ⁿ T(0), where T is the Taylor polynomial of order n of f expanded at t (TauCeti.iteratedDeriv_div_id). Since (-1)ⁿ f⁽ⁿ⁺¹⁾ ≥ 0, the Taylor remainder has a sign on every [ε, t] with ε > 0, giving T(ε) ≥ f(ε) ≥ 0 (TauCeti.le_taylorWithinEval_of_neg_one_pow_mul_iteratedDerivWithin_nonneg), and T(0) ≥ 0 follows by letting ε → 0.

Main declarations #

References #

If f is differentiable and nonnegative on (0, ∞) and its derivative is completely monotone there, then t ↦ f(t) / t is completely monotone on (0, ∞).

A Bernstein function divided by its parameter is completely monotone on (0, ∞).