Inversion of the parameter of Stieltjes and complete Bernstein functions #
The substitution t ↦ t⁻¹ exchanges the two ends of (0, ∞), and the Stieltjes class is
stable under the normalized substitution f ↦ (t ↦ f(t⁻¹) / t). On representing data it acts by
exchanging the singular coefficient a of a / t with the constant coefficient b, and by the
measure transformation
μ ↦ ν, the image of x⁻¹ μ(dx) under x ↦ x⁻¹,
because for x > 0 the kernels satisfy (t⁻¹ + x)⁻¹ / t = x⁻¹ (t + x⁻¹)⁻¹. This measure
transformation, MeasureTheory.Measure.stieltjesInversion, preserves the Stieltjes weight
condition, never charges 0, and is an involution on measures without an atom at 0.
Consequently the substitution is an involution of the Stieltjes class modulo equality on
(0, ∞).
Combined with the correspondence f ↦ t f(t) between Stieltjes and complete Bernstein functions,
this yields two further standard dualities: f is Stieltjes exactly when t ↦ f(t⁻¹) on
(0, ∞) extends to a complete Bernstein function, and for a complete Bernstein function f, the
function t ↦ t f(t⁻¹) on (0, ∞) extends to a complete Bernstein function.
Main declarations #
MeasureTheory.Measure.stieltjesInversion: the measure transformationμ ↦ (x⁻¹ • μ).inv.MeasureTheory.Measure.integral_stieltjesInversion,MeasureTheory.Measure.lintegral_stieltjesInversionandMeasureTheory.Measure.integrable_stieltjesInversion_iff: integration against the transformed measure.MeasureTheory.Measure.stieltjesInversion_singleton_zeroandMeasureTheory.Measure.integrable_weight_stieltjesInversion_iff: the transform never charges0and preserves the Stieltjes weight condition.MeasureTheory.Measure.stieltjesInversion_stieltjesInversion: the transformation is an involution on measures without an atom at0.TauCeti.RepresentsStieltjes.comp_inv_divandTauCeti.representsStieltjes_comp_inv_div_iff: the effect of the substitution on representing data.TauCeti.IsStieltjesFunction.comp_inv_divandTauCeti.isStieltjesFunction_comp_inv_div_iff: the Stieltjes class is invariant under the substitution.TauCeti.isStieltjesFunction_iff_exists_isCompleteBernsteinFunction_eqOn_comp_inv:fis Stieltjes exactly whent ↦ f(t⁻¹)has a complete Bernstein extension.TauCeti.IsCompleteBernsteinFunction.exists_isCompleteBernsteinFunction_eqOn_mul_comp_inv: for a complete Bernstein functionf, the functiont ↦ t f(t⁻¹)on(0, ∞)has a complete Bernstein extension.
References #
- R. Schilling, R. Song, Z. Vondraček, Bernstein Functions: Theory and Applications, de Gruyter, 2nd ed. (2012), Chapter 7.
The measure transformation dual to the substitution t ↦ t⁻¹ in a Stieltjes
representation: the image of the measure x⁻¹ μ(dx) under x ↦ x⁻¹. The density x⁻¹ is
taken in ℝ≥0, so it vanishes at x = 0 and the transformed measure never charges 0.
Equations
- μ.stieltjesInversion = (μ.withDensity fun (x : NNReal) => ↑x⁻¹).inv
Instances For
Integration against stieltjesInversion μ in terms of μ.
Integrability against stieltjesInversion μ in terms of μ.
The transformed measure never charges 0, because its density vanishes there.
Applying stieltjesInversion twice removes exactly the atom at 0.
stieltjesInversion is an involution on measures without an atom at 0.
The transformed measure satisfies the Stieltjes weight condition exactly when the restriction
of the original measure to (0, ∞) does. Indeed x⁻¹ (1 + x⁻¹)⁻¹ = (1 + x)⁻¹ for x > 0.
Inversion of a Stieltjes representation. If (μ, a, b) represents f, then
t ↦ f(t⁻¹) / t is represented by (stieltjesInversion μ, b, a): the singular and constant
coefficients are exchanged.
The substitution f ↦ (t ↦ f(t⁻¹) / t) is reversible on representing data: (ν, b, a)
represents t ↦ f(t⁻¹) / t exactly when (stieltjesInversion ν, a, b) represents f, for any
ν without an atom at 0.
If f is a Stieltjes function, then so is t ↦ f(t⁻¹) / t.
The Stieltjes class is invariant under the involution f ↦ (t ↦ f(t⁻¹) / t).
Stieltjes functions and complete Bernstein functions under inversion. A function f is
Stieltjes exactly when t ↦ f(t⁻¹) on (0, ∞) extends to a complete Bernstein function on
[0, ∞).
Duality of complete Bernstein functions. If f is a complete Bernstein function, then
t ↦ t f(t⁻¹) on (0, ∞) extends to a complete Bernstein function on [0, ∞).