Uniqueness of the Stieltjes and complete Bernstein representations #
A Stieltjes function determines the data representing it: if
f t = a / t + b + ∫ (t + x)⁻¹ dμ(x) for all t > 0
with a, b ≥ 0 and μ a measure on ℝ≥0 without an atom at the origin whose standard weight
x ↦ (1 + x)⁻¹ is integrable, then a, b and μ are uniquely determined by f. This is the
uniqueness half of the Stieltjes representation, and it transfers verbatim to complete Bernstein
functions through TauCeti.RepresentsCompleteBernstein.representsStieltjes_div.
The three pieces of data are separated one at a time.
- The coefficient
bis the limit offat+∞, because the Stieltjes integral vanishes there (TauCeti.tendsto_integral_inv_add_atTop_nhds_zero) and so doesa / t. - The singular coefficient
ais the mass that the measurea • δ₀ + μputs at the origin, sincea / tis exactly the Stieltjes integral ofa • δ₀. So oncebis known, the whole representation is the Stieltjes transform of a single measure, and it remains to show that a measure is determined by its Stieltjes transform. - That determinacy (
TauCeti.Measure.ext_of_integral_inv_add_eventuallyEq) reduces to Laplace determinacy for finite measures. Differentiating the Stieltjes transformntimes att = 1(TauCeti.iteratedDeriv_integral_inv_add) recovers the numbers∫ (1 + x)^{-1-n} dμ, which are the values at the natural numbers of the Laplace transform of the finite measure obtained by weightingμwith(1 + x)⁻¹and pushing it forward alongx ↦ log (1 + x). A finite measure onℝ≥0is determined by those values (TauCeti.Measure.ext_of_forall_laplaceTransform_natCast_eq), and both the pushforward and the weighting are invertible.
Main declarations #
TauCeti.tendsto_integral_inv_add_atTop_nhds_zero: a Stieltjes transform vanishes at+∞.TauCeti.Measure.ext_of_integral_inv_add_eventuallyEq: a measure onℝ≥0with integrable Stieltjes weight is determined by the germ of its Stieltjes transform at1.TauCeti.RepresentsStieltjes.uniqueandTauCeti.IsStieltjesFunction.existsUnique_representsStieltjes: uniqueness of the Stieltjes representation.TauCeti.RepresentsCompleteBernstein.uniqueandTauCeti.IsCompleteBernsteinFunction.existsUnique_representsCompleteBernstein: uniqueness of the complete Bernstein representation.
References #
- R. Schilling, R. Song, Z. Vondraček, Bernstein Functions: Theory and Applications, de Gruyter, 2nd ed. (2012), Theorem 2.2 and Theorem 6.2.
The Stieltjes transform at infinity #
A Stieltjes transform vanishes at infinity. The integrand (t + x)⁻¹ is dominated by the
standard Stieltjes weight once t ≥ 1, and tends to 0 pointwise.
Determinacy of a measure by its Stieltjes transform #
The Stieltjes weight is turned into an exponential by the substitution y = log (1 + x), whose
inverse is x = exp y - 1; both are recorded as self-maps of ℝ≥0, so that the transported
measure is again a measure on ℝ≥0.
A measure on ℝ≥0 whose Stieltjes weight is integrable is determined by the germ of its
Stieltjes transform at 1.
Uniqueness of the representing data #
The singular coefficient is absorbed into the representing measure as an atom at the origin, which turns a Stieltjes representation into an additive constant plus a single Stieltjes transform.
Uniqueness of the Stieltjes representation. A Stieltjes function determines its singular coefficient, its additive constant, and its representing measure.
Uniqueness of the complete Bernstein representation. A complete Bernstein function determines its two coefficients and its representing measure, because dividing by the parameter turns it into a Stieltjes function with the same data.
The Stieltjes representation theorem, uniqueness form. A Stieltjes function has exactly
one representing triple (a, b, μ).
The complete Bernstein representation theorem, uniqueness form. A complete Bernstein
function has exactly one representing triple (a, b, μ).