The Gauss–Bonnet formula for convex hyperbolic polygons with ideal vertices #
The invariant area of a convex hyperbolic polygon with n vertices in ℍ ∪ ∂ℍ and interior
angles α₀, …, αₙ₋₁ (with αᵢ = 0 at an ideal vertex) is (n - 2) π - (α₀ + ⋯ + αₙ₋₁)
(ConvexPolygon.volume_carrier). In particular the area is finite
(ConvexPolygon.volume_carrier_ne_top), the angle sum is at most (n - 2) π
(ConvexPolygon.sum_interiorAngle_le), an ideal polygon has area (n - 2) π, and an ideal
triangle has area π.
A polygon without ideal vertices is a compact convex polygon, whose area is
CompactConvexPolygon.volume_carrier. A polygon with an ideal vertex has the area and angle sum
of a convex polygon whose vertex 0 is ∞ (ConvexPolygon.exists_vertex_zero_eq_infty). For
such a polygon the area of the part of the carrier to the left of the vertical through vertex k
is the sum of the areas of the first k - 1 triangles of the fan from ∞
(ConvexPolygon.volume_carrier_inter_re_le_of_vertex_zero), and the angle sum is the sum of
the finite angles of these triangles (ConvexPolygon.sum_interiorAngle_eq_of_vertex_zero). In
these statements the vertices are indexed by natural numbers k, cast to Fin n under
open Fin.NatCast.
Main results #
ConvexPolygon.volume_carrier: Gauss–Bonnet for convex polygons with ideal vertices.ConvexPolygon.volume_carrier_ne_top,ConvexPolygon.toReal_volume_carrier: the area is finite, equal to the angular defect.ConvexPolygon.sum_interiorAngle_le: the angular defect is nonnegative.ConvexPolygon.volume_carrier_of_forall_eq_inr: an ideal polygon has area(n - 2) π;ConvexPolygon.volume_carrier_three_of_forall_eq_inr: an ideal triangle has areaπ.ConvexPolygon.volume_carrier_three_of_vertex_one_of_vertex_two: a triangle with two ideal vertices has areaπ - α, for its angleαat the third vertex.
Source #
Walkden, Hyperbolic geometry (MATH32051 lecture notes, Manchester 2019), Theorem 7.2.1 and
Remark 2 after it (an ideal triangle has area π), Theorem 7.2.2 and its proof ("Cut up P into
triangles. Apply Theorem 7.2.1 to each triangle and then sum the areas."), with ideal vertices as
in §7.1; Katok, Fuchsian groups, geodesic flows…, Clay Math. Proc. 10 (2010), Theorem 5.4.
A polygon with an ideal vertex at ∞ #
If vertex 0 is ∞, the angle sum is the sum of the finite angles of the triangles of the
fan from ∞, indexed by the casts to Fin n of the natural numbers 1 ≤ k < n - 1.
If vertex 0 is ∞, the area of the part of the carrier to the left of the vertical through
vertex k, for 0 < k < n, is the sum of the areas π - αⱼ - βⱼ of the first k - 1 triangles
of the fan from ∞, where αⱼ, βⱼ are the angles of the j-th triangle at vertex j and
vertex (j + 1).
The Gauss–Bonnet formula for a convex polygon whose vertex 0 is ∞.
The angular defect of a convex polygon whose vertex 0 is ∞ is nonnegative.
Gauss–Bonnet #
The Gauss–Bonnet formula for convex hyperbolic polygons with ideal vertices: the area of
a convex polygon with n vertices in ℍ ∪ ∂ℍ is (n - 2) π minus the sum of its interior
angles, the angle at an ideal vertex being 0.
Source: Walkden, Hyperbolic geometry (MATH32051), Theorem 7.2.2 and §7.1.
The angular defect of a convex polygon is nonnegative: the sum of its interior angles is at
most (n - 2) π.
A convex polygon has finite area.
The area of a convex polygon, as a real number, is its angular defect.
An ideal polygon, with all n vertices on ∂ℍ, has area (n - 2) π.
An ideal triangle has area π.
Source: Walkden, Hyperbolic geometry (MATH32051), Remark 2 after Theorem 7.2.1.
A triangle with two ideal vertices has area π - α, for its angle α at the third
vertex.