Uniqueness of Fourier coefficients and Fourier coefficients of products on the circle #
Mathlib's fourierCoeff f n = ∫ t, e_{-n}(t) • f t is defined for every function f on
AddCircle T, and Parseval's theorem shows that an L² function is determined by its Fourier
coefficients. This file proves the corresponding statements for integrable functions and for
products of two square-integrable functions, which in general are only integrable.
Uniqueness. An integrable function, with values in any complete normed complex space, whose
Fourier coefficients all vanish is zero almost everywhere. Integration against f is a continuous
linear functional on C(AddCircle T, ℂ) of norm at most ‖f‖₁; it vanishes on the monomials by
hypothesis, hence on the uniformly dense span of trigonometric polynomials and on every continuous
function. An integrable function orthogonal to all bounded continuous functions vanishes almost
everywhere (MeasureTheory.Integrable.ae_eq_zero_of_forall_integral_smul_eq_zero).
Products. If f and g are square integrable, then f * g is integrable (Mathlib's
MeasureTheory.MemLp.integrable_mul) and its Fourier coefficients are the convolution of those of
f and g: (f g)^(n) = ∑ₘ f̂(m) ĝ(n - m), the series converging
unconditionally. This is Parseval's
identity ⟪u, v⟫ = ∑ₘ conj(û(m)) v̂(m) for u = conj f and v = e_{-n} g. Consequently, if the
Fourier coefficients of f and g vanish below a and b respectively, then those of f * g
vanish below a + b, and similarly above.
Together these compute products in the boundary Hardy theory: for instance, if f has only
negative and g only nonpositive Fourier modes, then all modes of f * g are negative, and a
product of square-integrable functions with no Fourier modes at all is zero almost everywhere.
This is the Fourier-analytic input to Coburn's theorem that a nonzero Toeplitz operator or its
adjoint is injective.
Main results #
MeasureTheory.Integrable.ae_eq_zero_of_forall_fourierCoeff_eq_zero: an integrable function on the circle with vanishing Fourier coefficients is zero almost everywhere;MeasureTheory.Integrable.ae_eq_of_forall_fourierCoeff_eq: integrable functions with the same Fourier coefficients agree almost everywhere;MeasureTheory.MemLp.hasSum_fourierCoeff_mul: for square-integrablefandg,(f g)^(n) = ∑ₘ f̂(m) ĝ(n - m);MeasureTheory.MemLp.fourierCoeff_mul_eq_zero_of_lt_addandMeasureTheory.MemLp.fourierCoeff_mul_eq_zero_of_add_lt: one-sided spectral support of a product.
References #
- Y. Katznelson, An Introduction to Harmonic Analysis, third edition, Cambridge University Press (2004), Chapter I, §§1–2 (Fourier coefficients of products, and uniqueness).
- E. Park, Toeplitz operators, for the use of these facts in Coburn's theorem.
Uniqueness of Fourier coefficients for integrable functions. An integrable function on the circle whose Fourier coefficients all vanish is zero almost everywhere.
Integrable functions on the circle with the same Fourier coefficients agree almost everywhere.
Fourier coefficients of a product. If f and g are square integrable on the circle,
then the Fourier coefficients of f * g are the convolution of those of f and g:
(f g)^(n) = ∑ₘ f̂(m) ĝ(n - m).
If the Fourier coefficients of the square-integrable functions f and g vanish below a and
b respectively, then those of f * g vanish below a + b.
If the Fourier coefficients of the square-integrable functions f and g vanish above a and
b respectively, then those of f * g vanish above a + b.