Dilated cutoffs with Laplacian bounds #
In a finite-dimensional real inner product space, dilating a fixed smooth bump by R gives cutoffs
χ_R, equal to 1 on ball 0 R and to 0 off closedBall 0 (2R), with
‖Dχ_R‖ = O(1/R) and |Δχ_R| = O(1/R²) uniformly in R
(TauCeti.exists_forall_contDiff_cutoff_ball_norm_laplacian_le). These are the truncations used
to localize solutions of the Poisson equation: the error Δ(χ_R u) - χ_R Δu lives on the annulus
R ≤ ‖x‖ ≤ 2R and is controlled by the decay of u and Du there.
In dimension two the bound |Δχ_R| = O(1/R²) makes ∫ |Δχ_R| bounded uniformly in R, so
∫ Δχ_R f → 0 for every f tending to 0 at infinity
(TauCeti.tendsto_integral_laplacian_smul_of_tendsto_cocompact). This lets identities tested
against χ_R pass to R → ∞.
Dilated cutoffs with Laplacian bounds. There is a constant C such that for every R > 0
some smooth compactly supported χ equals 1 near every point of ball 0 R, equals 0 near
every point outside closedBall 0 (2R), and satisfies 0 ≤ χ ≤ 1, ‖Dχ‖ ≤ C / R and
|Δχ| ≤ C / R². The cutoff is x ↦ b (R⁻¹ • x) for a fixed smooth bump b equal to 1 on
closedBall 0 1 and supported in closedBall 0 2.
Laplacians of planar cutoffs against decaying functions. In a two-dimensional space, let
the cutoffs χ i equal 1 near ball 0 (R i) and 0 near the complement of
closedBall 0 (2 * R i), with |Δ χ i| ≤ C / (R i)² and R i → ∞. Then ∫ Δ χ i • f → 0 for
every f tending to 0 at infinity, since ∫ |Δ χ i| is bounded uniformly in i.