Hyperbolic operators have Lyapunov forms #
In finite dimensions, a bounded operator A on a real inner product space has a Lyapunov form
(ContinuousLinearMap.HasLyapunovForm: a symmetric S and c > 0 with
c ‖v‖² ≤ ⟪S (A v), v⟫) exactly when A is hyperbolic, that is, when its complexification has
no eigenvalue on the imaginary axis. In real terms, there are no ω : ℝ and v, w : E, not both
zero, with A v = -ω w and A w = ω v. The forward implication is
ContinuousLinearMap.HasLyapunovForm.eq_zero_of_apply_eq_neg_smul_of_apply_eq_smul; this file
proves the converse, the existence half of the inertia theorem of Ostrowski and Schneider.
The construction is first carried out over ℂ, by induction on the dimension, along a unitary
triangularization. Let u be a unit eigenvector of A, with eigenvalue λ, and let K = u^⊥.
In the splitting F = ℂ u ⊕ K, A is block upper triangular,
A (a u + k) = (λ a + ⟪u, A k⟫) u + Q k,
where Q is the compression of A to K. Every eigenvalue of Q is an eigenvalue of A, by
ContinuousLinearMap.hasEigenvalue_of_hasEigenvalue_compression_orthogonal_span_singleton, so Q
has a Lyapunov form S_K by induction. Then S = re λ • P_u + t • S_K P_K, with P_u and P_K
the orthogonal projections, satisfies
re ⟪S (A v), v⟫ ≥ (re λ)² |a|² - |re λ| ‖A‖ |a| ‖k‖ + t c_K ‖k‖²,
and for t large the right side is at least (re λ)² ‖v‖² / 2. Over ℝ, the operator is
complexified (ContinuousLinearMap.complexifyL2); the absence of imaginary eigen-pairs says that
the complexification has no eigenvalue on the imaginary axis, and the real part of its complex
Lyapunov form, restricted to real vectors, is a real Lyapunov form of A.
Combined with TauCeti.WeakDerivStep.isFredholm_trajectoryOperator_of_hasLyapunovForm, this shows
that d/ds + A(s) is Fredholm from W^{1,2} to L² for every continuous family A whose limits
at ±∞ are hyperbolic.
Main declarations #
ContinuousLinearMap.exists_isSymmetric_forall_mul_norm_sq_le_re_inner_of_re_ne_zero: an operator on a finite-dimensional complex inner product space without eigenvalues on the imaginary axis has a self-adjointSandc > 0withc ‖v‖² ≤ re ⟪S (A v), v⟫.ContinuousLinearMap.hasLyapunovForm_iff_forall_eq_zero_of_apply_eq_neg_smul_of_apply_eq_smul: on a finite-dimensional real inner product space,Ahas a Lyapunov form if and only if it has no purely imaginary eigenvalue.
References #
- A. Ostrowski and H. Schneider, Some theorems on the inertia of general matrices, J. Math. Anal. Appl. 4 (1962), 72–84.
- R. A. Horn and C. R. Johnson, Topics in Matrix Analysis, Cambridge University Press, 1991, §2.4 (the inertia theorem).
Lyapunov forms over ℂ. If no eigenvalue of an operator A on a finite-dimensional
complex inner product space lies on the imaginary axis, then there are a self-adjoint S and
c > 0 with c ‖v‖² ≤ re ⟪S (A v), v⟫ for every v.
Hyperbolic operators have Lyapunov forms. On a finite-dimensional real inner product
space, an operator A has a Lyapunov form if and only if it has no purely imaginary eigenvalue:
there are no ω and v, w, not both zero, with A v = -ω • w and A w = ω • v. This is the
existence half of the inertia theorem of Ostrowski and Schneider.