Almost-everywhere invariance and dominated convergence for projection-valued integrals #
Let P be a projection-valued measure on X acting on a complex Hilbert space H, with
diagonal measures P.diag ξ. The operator integral P.integral f = ∫ f dP of a bounded Borel
symbol f satisfies the vector norm identity ProjValMeasure.norm_sq_integral_apply,
‖(∫ f dP) ξ‖ ^ 2 = ∫ ‖f x‖ ^ 2 d(P.diag ξ)(x).
It identifies the map f ↦ (∫ f dP) ξ as an isometry from the symbols, with the L² norm of
P.diag ξ, into H, and transfers scalar integration theory to the operator integral:
- the integral only sees the symbol
P-almost everywhere, and in fact two symbols have the same integral exactly when they agreeP-almost everywhere; - uniformly bounded symbols converging
P-almost everywhere have integrals converging strongly, that is on every vector, by Lebesgue's dominated convergence theorem.
Strong convergence is the right conclusion here: the indicators of (0, 1 / (n + 1)) converge
pointwise to 0 on ℝ, but the norm of their integral is 1 against any projection-valued
measure that charges every such interval.
Main declarations #
ProjValMeasure.integral_eq_integral_iff:∫ f dP = ∫ g dPifff = gP-almost everywhere.ProjValMeasure.integral_congr_ae: symbols equalP-almost everywhere have equal integrals.ProjValMeasure.tendsto_integral_apply_filter_of_dominated_convergence: boundedP-almost everywhere convergence of symbols gives strong convergence of their integrals.
References #
- W. Rudin, Functional Analysis, 2nd ed., McGraw–Hill, 1991, Theorem 12.21.
- K. Schmüdgen, Unbounded Self-adjoint Operators on Hilbert Space, Springer GTM 265, 2012, Section 4.2.
The integral of f against P vanishes exactly when f vanishes P-almost everywhere.
Two bounded Borel symbols have the same integral against P exactly when they agree
P-almost everywhere.
Bounded Borel symbols that agree P-almost everywhere have the same integral against P.
Dominated convergence for the integral against a projection-valued measure: if bounded
Borel symbols F n are eventually bounded by a common constant P-almost everywhere and
converge to f P-almost everywhere, then their integrals converge to the integral of f
strongly, that is on every vector.