The quotient (1 - exp (-a)) / a #
This basic file packages the power series representing (1 - exp (-a)) / a without requiring a
to be invertible. In a complete normed algebra over a normed characteristic-zero field the series is
summable at every point. It is the analytic factor in the differential of a Lie-group exponential
map.
Main results #
oneSubExpNegDivSelf: the series∑ n, (n + 1)!⁻¹ • (-a)ⁿ.summable_oneSubExpNegDivSelf: the series is summable in a complete normed algebra.commute_oneSubExpNegDivSelf: the series commutes with its argument.mul_oneSubExpNegDivSelf: multiplying the series byagives1 - exp (-a).oneSubExpNegDivSelf_mul: the corresponding right-multiplication identity.map_oneSubExpNegDivSelf: continuous ring homomorphisms preserve the series.
References #
- Lie groups and the Lie algebra correspondence roadmap, Deliverable A, Layer 1, "The conjugation formulas".
- Mathlib's
spectrum.exp_mem_exp, whose proof supplies the shifted-exponential series argument adapted here.
The value of (1 - exp (-a)) / a with its removable singularity filled in, defined by a power
series. The series is summable everywhere in the complete normed-algebra setting below.
Equations
- oneSubExpNegDivSelf 𝕂 a = FormalMultilinearSeries.ofScalarsSum (fun (n : ℕ) => (↑(n + 1).factorial)⁻¹) (-a)
Instances For
The defining series for oneSubExpNegDivSelf.
The quotient with its removable singularity filled in takes the value 1 at zero.
The filled-in quotient commutes with its argument.
The series defining oneSubExpNegDivSelf is summable in a complete normed algebra.
Multiplying the filled-in quotient on the left by its argument recovers its numerator.
Multiplying the filled-in quotient on the right by its argument recovers its numerator.
At an invertible argument, the filled-in quotient is left division by that argument.
At an invertible argument, the filled-in quotient is right division by that argument.
Any continuous ring homomorphism commutes with oneSubExpNegDivSelf.