Idempotents in the separating space of a homomorphism #
Let θ : A → B be a homomorphism of complex Banach algebras, not assumed continuous. An algebra
homomorphism can only shrink quasispectra, so the spectral radius of θ x is at most ‖x‖.
This rules out nonzero idempotents of B that lie both in the range of θ and in its
separating space: if θ (a n) → p = θ u with a n → 0, then the elements θ (u * a n * u) lie
in the corner p B p, tend to p, and have spectral radii tending to zero, which is impossible
near a nonzero idempotent. In particular, the separating space of a surjective homomorphism
contains no nonzero idempotent.
The structure theory of separating ideals produces a nonzero idempotent in every nonzero finite-dimensional separating ideal of a semisimple algebra; this obstruction is what excludes it for surjective homomorphisms.
Main results #
NonUnitalAlgHom.eq_zero_of_isIdempotentElem_of_mem_separatingSpace: an idempotent in the range and in the separating space ofθis zero.
References #
- H. G. Dales, Banach Algebras and Automatic Continuity, §5.2, in particular the treatment of the separating spaces of epimorphisms leading to Johnson's uniqueness-of-norm theorem.
- B. E. Johnson, The uniqueness of the (complete) norm topology, Bull. Amer. Math. Soc. 73 (1967), 537–539.
Separating spaces of homomorphisms contain no idempotents from the range. Let
θ : A → B be a homomorphism of complex Banach algebras, not assumed continuous. An idempotent
p of B lying both in the range of θ and in the separating space of θ is zero. For
surjective θ, the separating space contains no nonzero idempotent.