Completely continuous operators over a coefficient ring #
A continuous linear map u : M →L[R] N between seminormed modules over a ring R is
completely continuous (ContinuousLinearMap.IsCompletelyContinuous) if it can be approximated
uniformly by continuous maps of finite rank: for every ε > 0 there is a continuous v whose
range lies in a finitely generated submodule (LinearMap.IsFiniteRank) with
‖u x - v x‖ ≤ ε * ‖x‖ for all x. These are the operators of Serre's and Coleman's
Fredholm theory over Banach algebras such as affinoid algebras, where the scalar ring is not a
field and finite rank must be read relative to that ring.
The approximation is phrased through uniform bounds rather than through the operator norm, so
that the definition carries no junk value over scalar rings where continuous maps need not be
bounded. Over Tate scalars (TauCeti.NormedRing.IsTate), in particular over every nontrivially
normed field, it is approximation in the operator norm ContinuousLinearMap.ringOpNorm
(ContinuousLinearMap.isCompletelyContinuous_iff_ringOpNorm).
Over Tate scalars complete continuity is also a condition on lattices rather than norms: for a
bounded neighbourhood M₀ of zero in the source, such as a bounded open lattice, u is
completely continuous exactly when for every neighbourhood V of zero in the target some
continuous map g of finite rank satisfies (u - g)(M₀) ⊆ V. This is the form in which complete
continuity is stated for Banach modules given by lattices rather than by norms. The condition
involves only the set M₀ and the neighbourhoods of zero in the target, so different bounded open
lattices give the same notion, and so do equivalent norms (complete continuity is invariant under
continuous linear equivalences).
Completely continuous maps are closed under addition, scalar multiplication and uniform
approximation, under composition on either side with bounded continuous linear maps, and over
Tate scalars under composition on either side with arbitrary continuous linear maps. The
identity of a complete normed module is completely continuous exactly when the module is finitely
generated: an approximant of finite rank within distance 1 / 2 of the identity is surjective
(TauCeti.surjective_of_norm_sub_apply_le), so its range, which lies in a finitely generated
submodule, is everything. Consequently a completely continuous u with (1 - u) ^ n = 0 forces
the module to be finitely generated.
Main definitions #
ContinuousLinearMap.IsCompletelyContinuous: uniform approximability by continuous linear maps of finite rank, characterized byContinuousLinearMap.isCompletelyContinuous_iff.
Main results #
LinearMap.IsFiniteRank.isCompletelyContinuous: continuous maps of finite rank are completely continuous.ContinuousLinearMap.isCompletelyContinuous_of_forall_approx,ContinuousLinearMap.isCompletelyContinuous_of_tendsto,ContinuousLinearMap.isClosed_setOf_isCompletelyContinuous: complete continuity is closed under uniform approximation, under operator-norm limits over Tate scalars, and is a closed condition over a nontrivially normed field.ContinuousLinearMap.isCompletelyContinuous_iff_forall_mapsTo,Filter.HasBasis.isCompletelyContinuous_iff_forall_mapsTo: the lattice criterion over Tate scalars, for a bounded neighbourhood of zero in the source and all (or a basis of) neighbourhoods of zero in the target.ContinuousLinearMap.IsCompletelyContinuous.clm_comp,ContinuousLinearMap.IsCompletelyContinuous.comp_clm: the ideal property over Tate scalars, andContinuousLinearEquiv.comp_isCompletelyContinuous_iff,ContinuousLinearEquiv.isCompletelyContinuous_comp_iff: invariance under continuous linear equivalences, hence under equivalent norms.ContinuousLinearMap.IsCompletelyContinuous.clm_comp_of_bound,ContinuousLinearMap.IsCompletelyContinuous.comp_clm_of_bound: composition on either side with a bounded continuous linear map, over any ring.ContinuousLinearMap.isCompletelyContinuous_id_iff: the identity of a complete normed module is completely continuous if and only if the module is finitely generated.ContinuousLinearMap.IsCompletelyContinuous.finite_of_one_sub_pow_eq_zero: a completely continuousuwith(1 - u) ^ n = 0forces the module to be finitely generated.
References #
- J.-P. Serre, Endomorphismes complètement continus des espaces de Banach p-adiques, Publ. Math. IHÉS 12 (1962), 69–85, §§2–3.
- R. Coleman, p-adic Banach spaces and families of modular forms, Invent. Math. 127 (1997), 417–479, Appendix A.
- C. Johansson and J. Newton, Extended eigenvarieties for overconvergent cohomology, arXiv:1604.07739, §2.1.
A continuous linear map u is completely continuous if it is a uniform limit of
continuous linear maps of finite rank: for every ε > 0 there is a continuous linear v whose
range lies in a finitely generated submodule with ‖u x - v x‖ ≤ ε * ‖x‖ for every x.
Instances For
Unfolding ContinuousLinearMap.IsCompletelyContinuous: u is completely continuous iff for
every ε > 0 some continuous linear map of finite rank is uniformly ε-close to u.
A continuous linear map of finite rank is completely continuous.
Every continuous linear map into a finitely generated module is completely continuous.
Complete continuity is closed under uniform approximation. A continuous linear map that
is, for every ε > 0, uniformly ε-close to a completely continuous map is completely
continuous.
Complete continuity is invariant under negation.
A completely continuous map is approximated on every bounded set M₀ by continuous maps of
finite rank, up to an arbitrary neighbourhood V of zero: some g of finite rank maps M₀ into
V after subtraction from u.
Postcomposing a completely continuous map with a continuous linear map bounded by C, that is
with ‖g y‖ ≤ C * ‖y‖, gives a completely continuous map. Over Tate scalars every continuous
linear map is bounded (ContinuousLinearMap.IsCompletelyContinuous.clm_comp).
Precomposing a completely continuous map with a continuous linear map bounded by C, that is
with ‖f x‖ ≤ C * ‖x‖, gives a completely continuous map. Over Tate scalars every continuous
linear map is bounded (ContinuousLinearMap.IsCompletelyContinuous.comp_clm).
Over Tate scalars, a continuous linear map is completely continuous if and only if it is a limit of continuous maps of finite rank in the operator norm.
Over Tate scalars, an operator-norm limit of completely continuous maps is completely continuous.
The lattice criterion for complete continuity. Over Tate scalars, let M₀ be a bounded
neighbourhood of zero in M, such as a bounded open lattice. A continuous linear map u is
completely continuous if and only if for every neighbourhood V of zero in N some continuous
map g of finite rank satisfies (u - g)(M₀) ⊆ V.
The condition only involves the neighbourhoods of zero in N and the set M₀, so replacing M₀
by another bounded neighbourhood of zero does not change it.
The lattice criterion ContinuousLinearMap.isCompletelyContinuous_iff_forall_mapsTo with the
neighbourhoods of zero in N restricted to a basis, such as a basis of open lattices.
Over Tate scalars, postcomposing a completely continuous map with a continuous linear map gives a completely continuous map.
Over Tate scalars, precomposing a completely continuous map with a continuous linear map gives a completely continuous map.
Over Tate scalars, complete continuity is unchanged by postcomposition with a continuous linear equivalence; in particular it does not depend on the choice of an equivalent norm on the target.
Over Tate scalars, complete continuity is unchanged by precomposition with a continuous linear equivalence; in particular it does not depend on the choice of an equivalent norm on the source.
Over a nontrivially normed field, the completely continuous maps form a closed subset of the space of continuous linear maps.
The identity criterion. The identity of a complete normed module is completely continuous if and only if the module is finitely generated.
Over Tate scalars, a completely continuous endomorphism u of a complete normed module with
(1 - u) ^ n = 0 forces the module to be finitely generated, since u then has the right
inverse ∑_{k < n} (1 - u) ^ k.