The trajectory operator with a degenerate limit is not Fredholm #
Let A : ℝ → End(F) be an essentially bounded family of operators on a real Banach space F.
If some nonzero vector v satisfies A(s) v → 0 as s → ∞ (or as s → -∞), for instance
because A has a limit A⁺ with A⁺ v = 0, then the trajectory operator
D_A u = u' + A u : W^{1,2}(ℝ, F) → L²(ℝ, F)
is not Fredholm. Together with
TauCeti.WeakDerivStep.isFredholm_trajectoryOperator_of_hasLyapunovForm, this shows that for a
continuous family of operators on a finite-dimensional inner product space with symmetric limits
A±, D_A is Fredholm exactly when both limits are injective, that is, invertible
(TauCeti.WeakDerivStep.isFredholm_trajectoryOperator_iff, in
TauCeti.Analysis.ODE.EnergyEstimate.Lyapunov).
The proof constructs an escaping approximate kernel. Fix a smooth bump ψ supported in
(-1, 1), and put uₙ(s) = (n + 1)^(-1/2) ψ((s - cₙ) / (n + 1)) v up to a normalizing constant,
with centres cₙ so far out that ‖A(s) v‖ ≤ 1 / (n + 1) on the support of uₙ and the supports
are pairwise disjoint. Then ‖uₙ‖_{L²} = 1, ‖uₙ'‖_{L²} is of order 1 / (n + 1) and
‖D_A uₙ‖_{L²} → 0, while ‖uₙ - uₘ‖²_{L²} = 2 for n ≠ m. A Fredholm operator has closed range
and a finite-dimensional complemented kernel, so a bounded sequence on which it tends to zero has a
convergent subsequence (ContinuousLinearMap.tendsto_subseq_of_cauchySeq_comp). The sequence
uₙ has none.
Main declarations #
TauCeti.WeakDerivStep.not_isFredholm_trajectoryOperator_of_tendsto_atTopandTauCeti.WeakDerivStep.not_isFredholm_trajectoryOperator_of_tendsto_atBot: ifA(s) v → 0at+∞or at-∞for somev ≠ 0, thenD_Ais not Fredholm.
References #
- J. Robbin and D. Salamon, The spectral flow and the Maslov index, Bull. London Math. Soc.
27 (1995), 1--33, Theorem A (the operator
d/ds + A(s)is Fredholm exactly when the limits are invertible). - M. Schwarz, Morse Homology, Chapter 2 (linearized trajectory operators).
The escaping profiles #
The escaping approximate kernel #
The trajectory operator with a degenerate limit at +∞ is not Fredholm. If A(s) v → 0
as s → ∞ for some v ≠ 0, for instance because A tends to an operator A⁺ with A⁺ v = 0,
then u ↦ u' + A u from W^{1,2}(ℝ, F) to L²(ℝ, F) is not Fredholm. The coefficient of the
operator is any L∞ class AL of A.
The trajectory operator with a degenerate limit at -∞ is not Fredholm. If A(s) v → 0
as s → -∞ for some v ≠ 0, for instance because A tends to an operator A⁻ with A⁻ v = 0,
then u ↦ u' + A u from W^{1,2}(ℝ, F) to L²(ℝ, F) is not Fredholm. The coefficient of the
operator is any L∞ class AL of A.