Holomorphic Nemytskii maps on the circle Sobolev spaces #
For s > 1/2 the Fourier-coefficient Sobolev space H^s of the circle consists of continuous
functions and is an algebra. This file shows that it is also stable under holomorphic functions:
if F is holomorphic on an open set U ⊆ ℂ and u ∈ H^s takes values in U, then F ∘ u lies in
H^s, and the Nemytskii map u ↦ F ∘ u is holomorphic on the open set of such u. These are
the nonlinear maps of boundary values used in the Hardy decompositions of cut Riemann surfaces, for
instance products and quotients of nonvanishing boundary maps.
The proof expands F in Taylor series around a nearby trigonometric polynomial p. A
trigonometric polynomial extends to an entire periodic function, which maps a thin strip around the
real axis close to the values of p. Composed with the derivatives F^{(k)}, it stays holomorphic
and, by Cauchy's estimates, bounded by k! M / ε ^ k on that strip, so the Fourier coefficients of
F^{(k)} ∘ p decay exponentially (TauCeti.norm_fourierCoeff_le_of_differentiableOn_strip) and
‖F^{(k)} ∘ p‖_{H^s} ≤ k! B / ε ^ k. The product estimate of H^s then makes
∑ₖ (k!)⁻¹ (F^{(k)} ∘ p) (u - p) ^ k converge in H^s for u near p, to F ∘ u, and the same
series is a power series expansion of the Nemytskii map around p.
Main definitions #
TauCeti.CircleSobolev.nemytskii F u: the element ofH^swhose continuous representative isF ∘ u, when there is one (and0otherwise).
Main statements #
TauCeti.CircleSobolev.exists_toContinuousMap_eq_of_differentiableOn_strip: a function on the circle extending to a periodic function holomorphic and bounded on a strip lies in everyH^s,s > 1/2, with an explicit norm bound.TauCeti.CircleSobolev.toContinuousMap_nemytskii: forFholomorphic on an open setUandu ∈ H^swith values inU, the continuous representative ofnemytskii F uisF ∘ u.TauCeti.CircleSobolev.analyticOnNhd_nemytskii: the mapnemytskii Fis analytic on the open set ofu ∈ H^swith values inU.TauCeti.CircleSobolev.hasFDerivAt_nemytskii: its derivative atuis multiplication byF' ∘ u; atu = 0it is multiplication by the scalarF'(0)(TauCeti.CircleSobolev.hasFDerivAt_nemytskii_zero).
References #
- Y. Katznelson, An Introduction to Harmonic Analysis, 3rd ed., Cambridge University Press, 2004, Chapter I (Fourier coefficients of functions holomorphic in a strip).
- M. E. Taylor, Partial Differential Equations III, Chapter 13, Section 3 (Sobolev spaces as algebras and their stability under smooth functions).
- J. W. Robbin and D. A. Salamon, A construction of the Deligne–Mumford orbifold, J. Eur. Math. Soc. 8 (2006), 611–699 (nonlinear maps of boundary Sobolev spaces in Hardy decompositions).
Functions holomorphic in a strip lie in every H^s. A continuous function f on
AddCircle T which is the restriction of a T-periodic function g, holomorphic and bounded by
M on the closed strip |Im z| ≤ δ, is the continuous representative of an element of H^s,
s > 1/2, of norm at most M (∑ₙ (1 + |n|) ^ (2 s) e^{-4πδ|n|/T}) ^ (1/2).
Trigonometric polynomials in a strip #
The Nemytskii map #
The Nemytskii map of F : ℂ → ℂ on H^s, s > 1/2: it sends u to the element of H^s
whose continuous representative is F ∘ u, if there is one, and to 0 otherwise. The composition
is tested on the circle AddCircle 1; it does not depend on the length of the circle
(nemytskii_eq_of_forall_toContinuousMap_apply). For F holomorphic on an open set containing
the values of u, the composition F ∘ u always lies in H^s (toContinuousMap_nemytskii).
Instances For
The Nemytskii map is determined by continuous representatives: if the continuous
representative of w ∈ H^s is F ∘ u on some circle, then nemytskii F u = w.
Holomorphic functions act on H^s, s > 1/2. If F is holomorphic on an open set U
and the continuous representative of u ∈ H^s takes values in U, then F ∘ u is the continuous
representative of nemytskii F u ∈ H^s.
The holomorphic Nemytskii map is holomorphic. If F is holomorphic on an open set U,
then u ↦ nemytskii F u is analytic on the open subset of H^s, s > 1/2, of elements with
values in U (isOpen_setOf_forall_toContinuousMap_mem).
The Nemytskii map of an entire function is analytic on all of H^s, s > 1/2.
The derivative of the holomorphic Nemytskii map. If F is holomorphic on an open set U
and u ∈ H^s takes values in U, then the derivative of nemytskii F at u is multiplication by
nemytskii (deriv F) u, the element of H^s with continuous representative F' ∘ u.
At the zero function, the derivative of the Nemytskii map of F is multiplication by the
scalar F'(0).