Sobolev functions vanishing continuously on the boundary #
Let Ω be a bounded open set and 1 ≤ p < ∞. A function u ∈ W^{1,p}(Ω) that agrees almost
everywhere on Ω with a function g continuous on the closure of Ω and zero on its frontier
lies in W^{1,p}_0(Ω). So for a function continuous up to the boundary, the classical boundary
condition u = 0 on ∂Ω implies the Sobolev one, with no regularity of ∂Ω assumed.
The proof truncates. For k > 0 the truncation (u - k)⁺ vanishes outside the compact set
{x ∈ closure Ω | g x ≥ k}, which lies inside Ω because g vanishes on the frontier, so it
belongs to W^{1,p}_0(Ω). As k → 0 it tends to u⁺ in W^{1,p}(Ω): on a domain of finite
measure (u - k)⁺ is the positive part of u - k, and taking positive parts is continuous on
W^{1,p}(Ω) (TauCeti.W1p.continuous_posPart). The same argument applied to -u handles u⁻.
Main declarations #
TauCeti.exists_isCompact_inter_preimage_Ici_subset_subset: the superlevel sets{x ∈ Ω | k ≤ g x},k > 0, of a function vanishing on the frontier lie in a compact subset ofΩ.TauCeti.W1p.mem_w1p0Submodule_of_continuousOn_closure: a Sobolev function on a bounded domain that agrees with a function continuous on the closure and vanishing on the frontier lies inW^{1,p}_0(Ω).
References #
- D. Gilbarg, N. S. Trudinger, Elliptic Partial Differential Equations of Second Order,
Section 7.4 (truncations of Sobolev functions) and Section 7.5 (the spaces
W^{k,p}_0).
Superlevel sets stay away from the boundary. Let g be continuous on the closure of a
bounded set U of a proper metric space and zero on its frontier. For every k > 0 the
points of U where k ≤ g lie in a compact subset of U, namely closure U ∩ g ⁻¹' Ici k.
A Sobolev function vanishing continuously on the boundary lies in W^{1,p}_0(Ω). Let Ω
be bounded and 1 ≤ p < ∞. If u ∈ W^{1,p}(Ω) agrees almost everywhere on Ω with a function
g that is continuous on closure Ω and zero on frontier Ω, then u ∈ W^{1,p}_0(Ω). No
regularity of the boundary is assumed.