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TauCeti.Analysis.SpecialFunctions.Integrals.AbsSinExp

The Laplace transform of |sin| #

For 0 < a the rectified sine |sin t| has the Laplace transform

∫_{t > 0} |sin t| e^{-a t} dt = (1 + e^{-π a}) / ((1 - e^{-π a}) (1 + a²)),

and, since |sin| is even, the two-sided transform ∫_ℝ |sin t| e^{-a |t|} dt is twice that. One arch contributes ∫_0^π sin t e^{-a t} dt = (1 + e^{-π a}) / (1 + a²), and since |sin| is π-periodic every later arch contributes the same amount damped by a further factor e^{-π a}; summing the geometric series gives the closed form.

Main declarations #

The Laplace integral of sin over one arch. For every real a, ∫_0^π sin t e^{-a t} dt = (1 + e^{-π a}) / (1 + a²).

For 0 < a, the function t ↦ |sin t| e^{-a t} is integrable on (0, ∞): it is dominated by e^{-a t}.

theorem TauCeti.integral_abs_sin_mul_exp_neg_mul_Ioi {a : ℝ} (ha : 0 < a) :
∫ (t : ℝ) in Set.Ioi 0, |Real.sin t| * Real.exp (-(a * t)) = (1 + Real.exp (-(Real.pi * a))) / ((1 - Real.exp (-(Real.pi * a))) * (1 + a ^ 2))

The Laplace transform of |sin|. For 0 < a, ∫_{t > 0} |sin t| e^{-a t} dt = (1 + e^{-π a}) / ((1 - e^{-π a}) (1 + a²)).

For 0 < a, the function t ↦ |sin t| e^{-a |t|} is integrable on ℝ: it is dominated by e^{-a |t|}.

theorem TauCeti.integral_abs_sin_mul_exp_neg_mul_abs {a : ℝ} (ha : 0 < a) :
∫ (t : ℝ), |Real.sin t| * Real.exp (-(a * |t|)) = 2 * (1 + Real.exp (-(Real.pi * a))) / ((1 - Real.exp (-(Real.pi * a))) * (1 + a ^ 2))

The two-sided Laplace transform of |sin|. For 0 < a, ∫_ℝ |sin t| e^{-a |t|} dt = 2 (1 + e^{-π a}) / ((1 - e^{-π a}) (1 + a²)).