Duals of simple objects #
In a rigid monoidal abelian category whose tensor product is additive, the right dual of a simple
object is simple. Taking right adjoint mates is a bijection (A ⟶ B) ≃ (Bᘁ ⟶ Aᘁ) reversing
composition, with inverse the left adjoint mate, and every object Y is the right dual (ᘁY)ᘁ of
its left dual. So a monomorphism f : Y ⟶ Xᘁ is the mate of the epimorphism ᘁf : X ⟶ ᘁY, which
out of the simple object X is an isomorphism or zero.
This is what makes duality act on the simple isomorphism classes of a fusion category.
If the tensor unit is simple, the tensor product of two nonzero objects is nonzero
(TauCeti.not_isZero_tensorObj). The coevaluation 𝟙_ C ⟶ Y ⊗ Yᘁ of a nonzero object is nonzero,
hence a monomorphism out of the simple unit, and whiskering by X keeps it a monomorphism because
X ⊗ - is right adjoint to Xᘁ ⊗ -. So X ≅ X ⊗ 𝟙_ C embeds into (X ⊗ Y) ⊗ Yᘁ. Without a
simple unit this fails: in a multifusion category two distinct simple summands of the unit have
zero tensor product.
For a split simple member of an exact pairing, Frobenius reciprocity and Schur's lemma show that every morphism from the paired tensor product to the unit is a scalar multiple of the evaluation. Both choices of the simple member are available; they control the two categorical trace pairings.
References #
- [P. Etingof, S. Gelaki, D. Nikshych, V. Ostrik, Tensor categories][egno15], §4.8
In a rigid monoidal abelian category, the right dual of a simple object is simple.
In a right rigid monoidal preadditive category with kernels and simple tensor unit, the tensor product of two nonzero objects is nonzero.
If the right member of an exact pairing is split simple, every morphism from the paired tensor product to the unit is a scalar multiple of the evaluation.
If the left member of an exact pairing is split simple, every morphism from the paired tensor product to the unit is a scalar multiple of the evaluation.