Rigidity of automorphisms of a function field #
Let F / k be a function field of genus g with exact constant field k. An automorphism
σ ∈ Aut(F / k) that fixes 2g + 3 distinct rational places is the identity. This is the
rigidity statement behind the finiteness of Aut(F / k) in genus at least two: an automorphism
group acting on a finite set of at least 2g + 3 rational places embeds into the permutations
of that set.
Main results #
TauCeti.eq_one_of_two_mul_genus_add_three_le_card: an automorphism ofF / kfixing at least2g + 3rational places is the identity.TauCeti.eq_of_forall_smul_eq_of_two_mul_genus_add_three_le_card: two automorphisms agreeing on at least2g + 3rational places are equal.
References #
- H. Stichtenoth, Algebraic Function Fields and Codes, 2nd ed., GTM 254, Springer, 2009, Proposition 1.6.6 and Exercise 3.17.
- G. D. Villa Salvador, Topics in the Theory of Algebraic Function Fields, Birkhäuser, 2006, Chapter 9.
Rigidity of automorphisms of a function field (Stichtenoth, Exercise 3.17): over an exact
constant field, an automorphism of F / k fixing at least 2g + 3 distinct rational places is
the identity.
Automorphisms are determined by their action on 2g + 3 rational places: over an exact
constant field, two automorphisms of F / k that move each place of a set of at least 2g + 3
rational places to the same place are equal. Hence Aut(F / k) acts faithfully on every invariant
set of at least 2g + 3 rational places.