Finite extensions of the constant field #
A finite extension of constants yields a finite compositum over the original field, and a
separable extension of constants produces a separable compositum. Exactness of the original
constant field is needed for neither. The function-field theorem for arbitrary algebraic
extensions of constants is in ConstantExtension.Algebraic.
Under the hypotheses that make constant field extensions well behaved — the original constant
field k is exact in F and k' / k is separable — the compositum acquires no new separable
constants: no element of F · k' outside k' is separable over k'. Perfectness of k' upgrades
this to exactness: when k' is perfect — for instance when k is perfect and k' / k is
algebraic — every algebraic element is separable over k', so k' is the full field of constants
of F · k'. Perfectness cannot simply be dropped: over an imperfect k an inseparable constant
field extension can enlarge the field of constants beyond k'. For instance,
k = 𝔽_p(t, u) is exact in F = k(x, y) with y ^ p = t * x ^ p + u, but for k' = k(t ^ (1/p))
the element y - t ^ (1/p) * x of F · k' is a p-th root of u, and u ^ (1/p) ∉ k'.
Finite extensions of constants with as many elements as desired always exist, realized as
composita inside an algebraic closure of F. Over a finite constant field this is how arguments
that need many constants, such as choosing a vector outside finitely many proper subspaces, are
carried out after a finite constant field extension.
Main results #
TauCeti.finiteDimensional_of_constantCompositum_eq_top: a compositum with finite constants is finite over the original field.TauCeti.finiteDimensional_base_of_constantCompositum_eq_top: conversely, for an exactkand separablek' / k, a compositum finite over the original field has finite constants.TauCeti.isSeparable_of_constantCompositum_eq_top: the compositum of a separable constant field extension is separable over the original field.TauCeti.separableClosure_eq_bot_of_constantCompositum_eq_top: for a separable constant field extension of an exact constant field,k'is separably closed inF · k'.TauCeti.isIntegrallyClosedIn_of_constantCompositum_eq_top: for a separable constant field extension by a perfectk', in particular over a perfectk,k'is the exact constant field ofF · k'(Stichtenoth, Proposition 3.6.1(a)).
Reference #
H. Stichtenoth, Algebraic Function Fields and Codes, second edition, Section III.6, Proposition 3.6.1.
A compositum with finite constants is finite over the original field. The ambient field
F' is assumed to be precisely the compositum of F and k'.
Finiteness of the compositum detects finiteness of the constants: if k is exact in F,
k' / k is separable and the compositum F · k' is finite over F, then k' / k is finite. This
is the converse of TauCeti.finiteDimensional_of_constantCompositum_eq_top, by the degree identity
[F · k' : F] = [k' : k] of linear disjointness.
A separable extension of the constant field produces a separable compositum over the original field.
The constant field of the compositum #
The enlarged constant field is separably closed in the compositum: if k is the exact
constant field of F and k' / k is separable algebraic, then every element of F · k' that is
separable over k' is already a constant of k'.
This is Stichtenoth, Proposition 3.6.1(a), with perfectness of k replaced by the separability of
the constant in question; TauCeti.isIntegrallyClosedIn_of_constantCompositum_eq_top recovers the
statement of record over a perfect k.
The constant field of a constant field extension (Stichtenoth, Proposition 3.6.1(a)):
if k is the exact constant field of F, k' / k is separable and k' is perfect, then the
compositum F · k' has exact constant field k'. Stichtenoth's hypotheses — k perfect and
k' / k algebraic — are the special case in which Algebra.IsSeparable k k' is inferred and
PerfectField k' is Algebra.IsAlgebraic.perfectField k.
Together with TauCeti.IsFunctionField.of_constantCompositum_eq_top from
ConstantExtension.Algebraic, this makes F · k' / k' a function field with exact constant field
for an algebraic k' / k, so that its genus, its places and their degrees are the ones the theory
of constant field extensions compares with those of F / k.
Large finite extensions of constants #
Large finite constant field extensions exist: for every n, there is a finite extension
k' / k with more than n elements together with a field F', intermediate between F and its
algebraic closure, which is the compositum F · k'. The elements of k' are chosen among the
infinitely many elements of the algebraic closure of k in that of F.