The regular differentials of a function field with a rational subfield of index two #
Let F / k be a function field with exact constant field k and genus g, and let x ∈ F be
transcendental with [F : k(x)] = 2. The divisor (g - 1) · (x)_∞ is canonical
(TauCeti.divisorClass_sub_one_zsmul_poles_eq_canonicalClass), so it is the divisor of a Weil
differential ω₀. By the duality theorem the regular differentials Ω_F(0) are the multiples
z · ω₀ with z ∈ L((g - 1) · (x)_∞), and that space is spanned by 1, x, …, x^{g-1}. Hence
ω₀, x ω₀, …, x^{g-1} ω₀ is a k-basis of Ω_F(0), and the quotient of two regular
differentials always lies in k(x). For g ≥ 2 the quotient of x ω₀ by ω₀ is x itself, so
these quotients generate k(x): the regular differentials single out the rational subfield of
index two.
For the model y ^ 2 = f(x) with f squarefree of degree m ≥ 1, away from characteristic two,
the differential ω₀ is explicit: dx / y has divisor (g - 1) · (x)_∞. Indeed
(dx) = -2 (x)_∞ + Diff(F / k(x)), and at a place Q above a place P of k(x) with
ramification index e the three terms contribute as follows.
- Above a zero of
f:e = 2, the different exponent is1andord_Q y = 1. - Above any other finite place:
e = 1and both the different exponent andord_Q yvanish. - Above infinity, for
modd:e = 2, the different exponent is1,ord_Q y = -mandord_Q x = -2, so the coefficient ism - 3 = 2 (g - 1). - Above infinity, for
meven:e = 1, the different exponent is0,ord_Q y = -m / 2andord_Q x = -1, so the coefficient ism / 2 - 2 = g - 1.
So the regular differentials of y ^ 2 = f(x) are exactly p(x) dx / y with deg p < g.
Main results #
TauCeti.weilDifferentialFiltration_zero_eq_span_pow: if(ω₀) = (g - 1) · (x)_∞, thenΩ_F(0)is spanned byx ^ i · ω₀fori < g; these are linearly independent byTauCeti.linearIndependent_repartitionDualMul_pow.TauCeti.mem_adjoin_of_repartitionDualMul_eq: the quotient of two regular differentials lies ink(x).TauCeti.adjoin_setOf_repartitionDualMul_eq_adjoin: forg ≥ 2, these quotients generatek(x).TauCeti.weilDifferentialDivisor_repartitionDualMul_inv_weilDifferentialCotrace_of_sq_eq: fory ^ 2 = f(x), the differentialdx / yhas divisor(g - 1) · (x)_∞.TauCeti.weilDifferentialFiltration_zero_eq_span_of_sq_eq: the regular differentials ofy ^ 2 = f(x)are spanned byx ^ i dx / yfori < g.
References #
- H. Stichtenoth, Algebraic Function Fields and Codes, 2nd ed., GTM 254, Springer, 2009, Section VI.2.
A rational subfield of index two #
The regular differentials over a rational subfield of index two: if [F : k(x)] = 2 and
the Weil differential ω has divisor (g - 1) · (x)_∞, then the regular differentials are
spanned by ω, x ω, …, x^{g-1} ω. These are linearly independent
(TauCeti.linearIndependent_repartitionDualMul_pow), so they form a basis of Ω_F(0).
Quotients of regular differentials lie in the rational subfield of index two: if
[F : k(x)] = 2 and z · η = ω for regular Weil differentials ω and η ≠ 0, then z ∈ k(x).
Quotients of regular differentials generate the rational subfield of index two: if
[F : k(x)] = 2 and g ≥ 2, then the quotients z of regular Weil differentials, z · η = ω with
η ≠ 0, generate k(x). Each such quotient lies in k(x)
(TauCeti.mem_adjoin_of_repartitionDualMul_eq), and x is the quotient of x ω₀ by ω₀.
The model y ^ 2 = f(x) #
The divisor of dx / y: away from characteristic two, if F = k(x, y) with
y ^ 2 = f(x) for a squarefree polynomial f of degree m ≥ 1, then the Weil differential
dx / y has divisor (g - 1) · (x)_∞, where g = ⌊(m - 1) / 2⌋ is the genus of F and dx is
the cotrace of the normalized differential of k(x).
The regular differentials of y ^ 2 = f(x): away from characteristic two, if
F = k(x, y) with y ^ 2 = f(x) for a squarefree polynomial f of degree m ≥ 1, then the
regular Weil differentials of F are spanned by x ^ i dx / y for i < g, where
g = ⌊(m - 1) / 2⌋ is the genus of F and dx is the cotrace of the normalized differential of
k(x). They are linearly independent (TauCeti.linearIndependent_repartitionDualMul_pow
applied to dx / y), so they form a basis of Ω_F(0).