No coefficient field over the constants at an inseparable residue field #
At a place P of F / k whose residue field F_P is separable over k, the completed valuation
ring 𝒪̂_P contains a unique copy of F_P over k lifting the residue field
(TauCeti.Place.completionResidueFieldSection), and a uniformizer identifies 𝒪̂_P with
F_P[[T]] and the completion F̂_P with F_P((T)) over k
(TauCeti.Place.completionIntegersEquivPowerSeriesResidueField,
TauCeti.Place.completionEquivLaurentSeriesResidueField). This file shows that the separability
hypothesis of these constructions cannot be dropped.
Let k have characteristic p, let c ∈ k, and let z ∈ F be such that z ^ p - c has
positive order at P, not divisible by p. Then the value z(P) is a p-th root of c in
F_P, but c has no p-th root in F̂_P: if b ^ p = c, then z ^ p - c = (z - b) ^ p would
have order divisible by p. So there is no k-algebra map F_P → F̂_P at all, and in particular
no coefficient field over k and no k-linear identification of 𝒪̂_P with F_P[[T]] or of
F̂_P with F_P((T)); the residue field F_P is inseparable over k.
The hypotheses hold over every imperfect field. If a ∈ k is not a p-th power, the polynomial
X ^ p - a is irreducible, and at its place on k(x) the function x ^ p - a is a prime element.
For example, a may be the variable of k = 𝔽_p(a) (TauCeti.ratFunc_pow_ne_X). Expansions and
residues at places with inseparable residue field therefore cannot be set up over k in the way
they are at places with separable residue field. A coefficient field that is only linear over the
prime field still exists (TauCeti.Place.exists_completionResidueFieldSection), and through it
𝒪̂_P and F̂_P are still isomorphic to F_P[[T]] and F_P((T)) as rings
(TauCeti.Place.completionIntegersEquivPowerSeriesOfSection,
TauCeti.Place.completionEquivLaurentSeriesOfSection).
Main results #
TauCeti.Place.pow_ne_algebraMap_completion:chas nop-th root inF̂_P.TauCeti.Place.isEmpty_algHom_residueField_completion: there is nok-algebra mapF_P → F̂_P.TauCeti.Place.not_isSeparable_residueField:F_Pis not separable overk.TauCeti.Place.isEmpty_completionIntegers_algEquiv_powerSeriesandTauCeti.Place.isEmpty_completion_algEquiv_laurentSeries:𝒪̂_Pis notk-isomorphic toF_P[[T]], andF̂_Pis notk-isomorphic toF_P((T)).TauCeti.Place.isEmpty_completionIntegers_algEquiv_powerSeries_adicOfIrreducible_X_pow_sub_C: the example of the place of an irreducibleX ^ p - aonk(x).
References #
- H. Stichtenoth, Algebraic Function Fields and Codes, 2nd ed., GTM 254, Springer, 2009, Section IV.2, where the constant field is perfect throughout.
- J.-P. Serre, Local Fields, GTM 67, Springer, 1979, Chapter II, §4.
No p-th root of c in the completion. If z ^ p - c has order at P not divisible
by p, then the constant c is not a p-th power in F̂_P: otherwise z ^ p - c = (z - b) ^ p
there.
No k-algebra map from the residue field to the completion. If z ^ p - c has positive
order at P, not divisible by p, then z(P) is a p-th root of c in F_P, which F̂_P
does not have.
The residue field is inseparable over k when some z ^ p - c has positive order at P,
not divisible by p: otherwise TauCeti.Place.completionResidueFieldSection would be a
k-algebra map from F_P to the completion.
The completed valuation ring is not F_P[[T]] over k when some z ^ p - c has
positive order at P, not divisible by p: the separability hypothesis of
TauCeti.Place.completionIntegersEquivPowerSeriesResidueField cannot be dropped.
The completion is not F_P((T)) over k when some z ^ p - c has positive order at
P, not divisible by p: the separability hypothesis of
TauCeti.Place.completionEquivLaurentSeriesResidueField cannot be dropped.
The place of X ^ p - a over an imperfect field #
The completion of k(x) at the place of an irreducible X ^ p - a is not F_P[[T]] over
k: the residue field k[X] / (X ^ p - a) has no copy over k in the completed valuation
ring. For p prime, X ^ p - a is irreducible as soon as a is not a p-th power
(irreducible_X_pow_sub_C_of_prime), so this happens over every imperfect field, for example
over 𝔽_p(a) (TauCeti.ratFunc_pow_ne_X). The hypothesis p ≠ 1 excludes characteristic
zero, where the place of X - a is rational.