The tame character of a place #
Let F' / F be an extension of fields, k a subfield of F, and P a place of F' / k, and fix
a uniformizer t at P. An automorphism σ in the inertia group G_0(P) moves t by a unit,
σ t = u_σ t, and the value of u_σ at P is the tame character
TauCeti.Place.tameCharacter : G_0(P) →* (F'_P)ˣ. Because σ acts trivially on the residue field,
σ ↦ u_σ(P) is a homomorphism, and it does not depend on t. Its kernel consists of the
automorphisms with σ t ≡ t modulo 𝔪_P², so it contains the first ramification group G_1(P).
When the residue extension F'_P / F_{P ∩ F} is separable, the kernel is exactly G_1(P): the
value at P of a function z integral at P is a simple root of a polynomial over 𝒪_{P ∩ F},
and Taylor expansion of that polynomial at z shows that σ z ≡ z modulo 𝔪_P² as soon as
σ t ≡ t. Then G_0(P) / G_1(P) embeds in the multiplicative group of the residue field, so when
the inertia group is finite it is cyclic of order prime to the residue characteristic p.
Since G_1(P) is a p-group (TauCeti.Place.isPGroup_ramificationGroup_succ), the place has no
wild inertia exactly when p does not divide |G_0(P)|, which in a finite Galois extension is the
ramification index.
This is part of Stichtenoth, Proposition 3.8.5, which is stated over a perfect constant field, so
that all residue fields are perfect; here the only hypothesis is that the residue extension is
separable. Without it the kernel of the tame character can be strictly larger than G_1(P). The
analogous statements for nonarchimedean local fields are in
TauCeti/NumberTheory/LocalField/UnitFiltration/RamificationGroup.lean.
Main definitions #
TauCeti.Place.tameCharacter: for a uniformizertatP, the homomorphismσ ↦ (σ t / t)(P)fromG_0(P)to the units of the residue field.TauCeti.Place.tameCharacterGraded: the induced homomorphism onG_0(P) / G_1(P).
Main results #
TauCeti.Place.tameCharacter_eq_of_ord_eq_one: the tame character does not depend on the uniformizer.TauCeti.Place.tameCharacter_eq_one_iff:σlies in the kernel exactly whenσ t ≡ tmodulo𝔪_P².TauCeti.Place.mem_ramificationGroup_one_iff: for a separable residue extension, an element ofG_0(P)lies inG_1(P)exactly when it fixes a uniformizer modulo𝔪_P².TauCeti.Place.ker_tameCharacter: for a separable residue extension, the kernel of the tame character isG_1(P).TauCeti.Place.tameCharacterGraded_injective: for a separable residue extension, the induced tame character onG_0(P) / G_1(P)is injective.TauCeti.Place.isCyclic_quotient_ramificationGroup_oneandTauCeti.Place.not_dvd_index_ramificationGroup_one: for finite inertia and a separable residue extension,G_0(P) / G_1(P)is cyclic of order prime to the residue characteristic.TauCeti.Place.ramificationGroup_one_eq_bot_iff_not_dvd_card_ramificationGroup_zero: for finite inertia and a separable residue extension, the first ramification group is trivial exactly when the residue characteristic does not divide the order of the inertia group, andTauCeti.Place.ramificationGroup_one_eq_bot_iff_not_dvd_ramificationIdxits form for a finite Galois extension: no wild inertia exactly in the tame case.
References #
- H. Stichtenoth, Algebraic Function Fields and Codes, 2nd ed., GTM 254, Springer, 2009, Proposition 3.8.5.
The tame character (Stichtenoth, Proposition 3.8.5): for a uniformizer t at P, the
homomorphism from the inertia group G_0(P) to the units of the residue field sending σ to the
value at P of the unit σ t / t. It does not depend on t
(TauCeti.Place.tameCharacter_eq_of_ord_eq_one), and its kernel contains G_1(P), with equality
when the residue extension is separable (TauCeti.Place.ker_tameCharacter).
Equations
- TauCeti.Place.tameCharacter F P ht = MonoidHom.mk' (fun (g : ↥(TauCeti.Place.ramificationGroup F P 0)) => Units.mk0 ((IsLocalRing.residue ↥P.integers) ⟨↑↑g t * t⁻¹, ⋯⟩) ⋯) ⋯
Instances For
The value of the tame character at σ, computed on any representative y of σ t / t
in 𝒪_P.
The kernel of the tame character (Stichtenoth, Proposition 3.8.5): σ has trivial tame
character exactly when it fixes the uniformizer t modulo 𝔪_P².
The tame character does not depend on the uniformizer.
The tame character is trivial on the first ramification group: an automorphism moving every
function integral at P by an element of 𝔪_P² in particular fixes t modulo 𝔪_P².
The tame character induced on G_0(P) / G_1(P). It is injective when the residue extension
is separable (TauCeti.Place.tameCharacterGraded_injective).
Equations
- TauCeti.Place.tameCharacterGraded F P ht = QuotientGroup.lift ((TauCeti.Place.ramificationGroup F P 1).subgroupOf (TauCeti.Place.ramificationGroup F P 0)) (TauCeti.Place.tameCharacter F P ht) ⋯
Instances For
The induced tame character evaluated on the class of an inertia automorphism.
The induced tame character does not depend on the choice of uniformizer.
Membership in the first ramification group is decided at a uniformizer, when the residue
extension is separable (Stichtenoth, Proposition 3.8.5): an element of G_0(P) lies in G_1(P)
exactly when it fixes t modulo 𝔪_P².
The kernel of the tame character is the first ramification group, when the residue
extension is separable (Stichtenoth, Proposition 3.8.5): so G_0(P) / G_1(P) embeds in the
multiplicative group of the residue field.
The induced tame character is injective when the residue extension is separable.
The tame quotient G_0(P) / G_1(P) is cyclic when the inertia group is finite and the
residue extension is separable (Stichtenoth, Proposition 3.8.5): it embeds in the multiplicative
group of the residue field, whose finite subgroups are cyclic.
The index of G_1(P) in G_0(P) is prime to the residue characteristic p, when the
inertia group is finite and the residue extension is separable (Stichtenoth, Proposition 3.8.5):
G_0(P) / G_1(P) embeds in the multiplicative group of a field of characteristic p, which has
no element of order p.
A place has no wild inertia exactly when the residue characteristic p does not divide the
order of its inertia group, when that group is finite and the residue extension is separable:
G_1(P) is a p-group (TauCeti.Place.isPGroup_ramificationGroup_succ) of index prime to p.
A place of a finite Galois extension is tamely ramified exactly when it has no wild
inertia, when the residue extension is separable: the first ramification group is trivial if and
only if the residue characteristic p does not divide the ramification index.