The minimal polynomial of a primitive element of a Galois extension #
Let L/K be a finite Galois extension and let x generate L over K. The Galois group acts
freely on x, so the conjugates σ x for σ ∈ Gal(L/K) are exactly the roots of minpoly K x,
each once, and
(minpoly K x).map (algebraMap K L) = ∏ σ : Gal(L/K), (X - C (σ x)).
Differentiating and evaluating at x kills every summand with a factor X - C x and leaves
(minpoly K x)' (x) = ∏_{σ ≠ 1} (x - σ x).
This is the form in which the derivative of the minimal polynomial enters the theory of the
different: for a Galois extension of local fields it expresses the different exponent as a sum
of valuations v (σ x - x) over the nontrivial automorphisms.
Main results #
TauCeti.minpoly_map_eq_prod_X_sub_C_of_adjoin_eq_top: the minimal polynomial of a primitive element is, inL[X], the product ofX - C (σ x)over the Galois group.TauCeti.aeval_derivative_minpoly_eq_prod_of_adjoin_eq_top: its derivative atxis the product ofx - σ xover the nontrivial automorphisms.
References #
- J.-P. Serre, Corps Locaux, Chapter III, §6 and Chapter IV, §1.
The image in L[X] of the minimal polynomial of a primitive element x of a finite Galois
extension L/K is ∏ σ : Gal(L/K), (X - C (σ x)).
The derivative of the minimal polynomial of a primitive element x of a finite Galois
extension, evaluated at x, is ∏_{σ ≠ 1} (x - σ x).