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TauCeti.FieldTheory.GaloisGroups.Certificate.Cyclic.Basic

A cyclic quintic certificate #

The polynomial X⁵ + X⁴ - 4X³ - 3X² + 3X + 1 is irreducible modulo 2. Together with its second root X² - 2 in the root field, this supplies a cyclic-route certificate and proves that its Galois group has label 5T1. This polynomial defines the LMFDB number field 5.5.14641.1.

The file also computes the discriminant and the resolvent sextic of this quintic. Its roots are 2 cos (2πk/11), and if θ is one of them then so is θ² - 2; iterating, the five roots are polynomials of degree at most four in θ. The discriminant and the six values of Dummit's F₂₀-invariant at these roots are then polynomials in θ. Reduced modulo the quintic, the product of the differences of the roots is -121, and the six values become explicit elements of ℚ(θ). One of them is -16, and they are pairwise distinct because 1, θ, θ², θ³, θ⁴ are linearly independent over ℚ, the quintic being irreducible. So the resolvent sextic splits over ℚ(θ) with distinct roots, one of them -16. Every reduction modulo the quintic is a linear_combination with an explicit quotient.

Main results #

References #

The polynomial X² - 2 supplies formal second-root evidence for the cyclic quintic X⁵ + X⁴ - 4X³ - 3X² + 3X + 1. For this monic irreducible quintic, it represents a second root in the field generated by one root.

The reduction of the cyclic quintic modulo 2 is irreducible.

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The cyclic quintic has a single irreducible factor of degree five modulo 2.

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The cyclic-route certificate for the cyclic quintic checks.

The roots of the cyclic quintic over ℂ #

The discriminant #

The discriminant of the cyclic quintic X⁵ + X⁴ - 4X³ - 3X² + 3X + 1 is 121² = 11⁴, a square: the Galois group C₅ consists of even permutations.

The resolvent sextic #

The integer -16 is a root of the resolvent sextic of the cyclic quintic X⁵ + X⁴ - 4X³ - 3X² + 3X + 1, and that sextic has nonzero discriminant: over ℚ(θ), for a root θ of the quintic, it splits into six distinct linear factors.