Translating the variable, and depressed quartics #
Replacing f(X) by f(X + t) for a constant t of the base field moves every root of f by
-t. Since t is fixed by every automorphism over the base field, this changes neither the
splitting field nor the Galois action on the roots: the root sets correspond by x ↦ x + t,
equivariantly for every automorphism, and so the two Galois images are the same permutation group
read through that bijection. In particular f(X + t) and f carry the same transitive-group label.
The classical use is depression. Away from characteristic 2 the substitution X ↦ X - a/4
carries the quartic X⁴ + aX³ + bX² + cX + d to a quartic X⁴ + pX² + qX + r without cubic
term, with
p = b - 6s², q = c - 2bs + 8s³, r = d - cs + bs² - 3s⁴, s = a/4.
So the label of any quartic is the label of a depressed one, which is the form in which the
resolvent cubic TauCeti.resolventCubic is written.
Main results #
Polynomial.isSplittingField_comp_X_add_C_iff:f(X + t)andfhave the same splitting fields.Polynomial.galActionHom_restrict_rootSetCompXAddCEquiv: the bijectionPolynomial.rootSetCompXAddCEquivof root sets is equivariant for every automorphism of a normal extension in whichfsplits.Polynomial.map_range_galActionHom_comp_X_add_C: the Galois images off(X + t)andfcorrespond along that bijection.TauCeti.hasGaloisLabel_comp_X_add_C_iff:f(X + t)andfhave the same label.TauCeti.quartic_comp_X_sub_C,TauCeti.hasGaloisLabel_quartic_iff_depressed: the depression of a quartic, and its invariance of the label.
References #
- K. Conrad, Galois groups of cubics and quartics (not in characteristic 2), §1.
p(X + t) splits in an extension exactly when p does.
p(X + t) and p have the same splitting fields: the roots of one are the roots of the other
moved by an element of the base field, so they generate the same subalgebra.
The translation of roots is Galois-equivariant. For an automorphism ϕ of an extension
in which p splits, moving a root of p(X + t) by t and then applying ϕ agrees with applying
ϕ and then moving by t, since ϕ fixes t.
The Galois images of p(X + t) and p correspond. Read through the bijection
x ↦ x + t of root sets, the permutations of the roots of p(X + t) induced by its Galois group
are exactly those of the roots of p induced by the Galois group of p. The roots may be taken in
any normal extension in which p splits.
Translating the variable does not change the label. f(X + t) carries the
transitive-group label j exactly when f does.
The depression of a quartic. Substituting X - s into X⁴ + 4s X³ + bX² + cX + d
removes the cubic term. The identity holds over every commutative ring.
Depression does not change the label. Away from characteristic 2, the quartic
X⁴ + aX³ + bX² + cX + d carries the same label as the depressed quartic X⁴ + pX² + qX + r
obtained from it by the substitution X ↦ X - a/4.