Galois groups over ℚ from factorizations modulo primes #
Let f be a monic integral polynomial and p a prime not dividing disc f. Dedekind's theorem,
TauCeti.NumberField.exists_gal_fullCycleType_eq_factorizationType, says that the degrees of the
irreducible factors of f mod p are the cycle lengths, fixed points included, of some element of
the Galois group of f over ℚ acting on the complex roots of f. This file reads that theorem
as membership of the factorization type in the set of full cycle types of the Galois image, and
draws the consequences for the Galois group.
A factorization type exhibits an element of the Galois image, so it only ever bounds the image from below. The shapes read off here are:
- an irreducible reduction exhibits a cycle through all the roots;
- a reduction with exactly one quadratic factor, all its other factors being of odd degree, exhibits a transposition, as an odd power of the element it produces;
- a reduction whose only factor of degree at least two is a cubic exhibits a
3-cycle.
Combined with the recognition theorems for permutation groups, these give the classical
criteria for a large Galois group. In prime degree, irreducibility over ℚ and a transposition
force the full symmetric group. In any degree, irreducibility over ℚ, a reduction of type
(1, n - 1) and a reduction with a single quadratic factor and odd other factors force the full
symmetric group: the first two make the Galois image doubly transitive, hence primitive, and a
primitive group containing a transposition is everything. This is the criterion behind van der
Waerden's construction of integral polynomials of every degree with Galois group Sₙ, where the
three reductions are prescribed modulo 2, 3 and 5.
Main results #
TauCeti.natCard_rootSet_complex_eq_natDegree: an integral polynomial with nonzero discriminant has as many distinct complex roots as its degree.TauCeti.exists_mem_range_galActionHom_fullCycleType_eq_factorDegrees: the factor degrees offmodulo a prime not dividingdisc fare the full cycle type of an element of the Galois image.TauCeti.lcm_factorDegrees_dvd_natCard_gal: the least common multiple of the factor degrees offmodulo a prime not dividingdisc fdivides the order of the Galois group.TauCeti.exists_isCycle_mem_range_galActionHom_of_irreducible_map: an irreducible reduction exhibits a cycle moving every root.TauCeti.not_irreducible_map_of_even_natDegree_of_range_le_alternatingGroup: an even-degree polynomial whose Galois image consists of even permutations has no irreducible reduction.TauCeti.exists_isSwap_mem_range_galActionHom: a reduction with one quadratic factor and odd other factors exhibits a transposition.TauCeti.exists_isThreeCycle_mem_range_galActionHom: a reduction whose only nonlinear factor is cubic exhibits a3-cycle.TauCeti.alternatingGroup_le_range_galActionHom: a primitive Galois image with a reduction whose only nonlinear factor is a cubic contains the alternating group.TauCeti.surjective_galActionHom_of_prime_natDegree: in prime degree, irreducibility and a reduction exhibiting a transposition give the full symmetric group.TauCeti.surjective_galActionHom_of_factorDegrees: irreducibility, a reduction of type(1, n - 1)and a reduction exhibiting a transposition give the full symmetric group.TauCeti.surjective_galActionHom_X_pow_five_sub_X_sub_one: the Galois group ofX ^ 5 - X - 1overℚis the full symmetric group on its five roots.
References #
- B. L. van der Waerden, Algebra I, Springer, §61.
- H. Cohen, A Course in Computational Algebraic Number Theory, Springer 1993, §6.3.
A prime candidate is good for an integral polynomial when it does not divide the polynomial discriminant.
Equations
- TauCeti.IsGoodPrime f p = ¬↑p ∣ f.discr
Instances For
The defining characterization of a good prime.
An integral polynomial with nonzero discriminant has as many distinct complex roots as its degree.
Factor degrees are a full cycle type of the Galois image. Let f be a monic integral
polynomial and p a prime not dividing disc f. Some permutation of the complex roots of f
induced by the Galois group of f over ℚ has as its cycle lengths, one part for each fixed
root, the degrees of the irreducible factors of f modulo p.
The polynomial f need not be irreducible.
Factorization types bound the order of the Galois group from below. Let f be a monic
integral polynomial and p a prime not dividing disc f. The least common multiple of the
degrees of the irreducible factors of f modulo p divides the order of the Galois group of f
over ℚ: it is the order of the element of the Galois image that the factorization exhibits.
A factorization type bounds the Galois image only from below: it exhibits an element of the image, which every larger permutation group also contains, so it cannot confine the image to a proper subgroup.
An irreducible reduction exhibits a full cycle. If a monic integral polynomial f of
degree at least two is irreducible modulo a prime p, then the Galois image of f over ℚ
contains a cycle moving every complex root of f.
No hypothesis on the discriminant is needed: an irreducible polynomial over the perfect field
ZMod p is separable, so p does not divide disc f.
If a monic integral polynomial has even degree at least two and its Galois action on the complex roots consists of even permutations, then its reduction modulo any prime is reducible. An irreducible reduction would exhibit a cycle through all the roots, which is odd in even degree.
A single quadratic factor exhibits a transposition. Let f be a monic integral
polynomial and p a prime not dividing disc f. If exactly one irreducible factor of f
modulo p is quadratic and all the others have odd degree, then the Galois image of f over
ℚ contains a transposition of the complex roots of f.
A single cubic factor exhibits a 3-cycle. Let f be a monic integral polynomial and
let p be a prime not dividing disc f. If the only irreducible factor of f modulo p of
degree at least two is a cubic, then the Galois image contains a 3-cycle.
A cubic factor forces the alternating group. Let f be a monic integral polynomial whose
Galois image over ℚ acts primitively on the complex roots of f, and let p be a prime not
dividing disc f. If the only irreducible factor of f modulo p of degree at least two is a
cubic, then the Galois image contains the alternating group of the roots.
The full symmetric group in prime degree. Let f be a monic integral polynomial of
prime degree, irreducible over ℚ, and let p be a prime not dividing disc f. If exactly one
irreducible factor of f modulo p is quadratic and all the others have odd degree, then the
Galois group of f over ℚ induces every permutation of the complex roots of f.
The full symmetric group from two reductions. Let f be a monic integral polynomial of
degree n, irreducible over ℚ, and let q and r be primes. Suppose that f modulo q is the
product of an irreducible factor of degree n - 1 and a linear factor, and that r does not
divide disc f, with exactly one irreducible factor of f modulo r quadratic and all the
others of odd degree. Then the Galois group of f over ℚ induces every permutation of the
complex roots of f.
Irreducibility over ℚ may itself come from a third prime, modulo which f is irreducible.
The quintic X ^ 5 - X - 1 #
The polynomial X ^ 5 - X - 1 is monic.
Modulo 2, the irreducible factors of X ^ 5 - X - 1 have the distinct degrees 3 and 2,
so the reduction is squarefree, hence separable, and 2 does not divide the discriminant.
The Galois group of X ^ 5 - X - 1 over ℚ is S₅.