Minimal polynomials over a relatively algebraically closed base field #
Let F / k be a field extension in which k is relatively algebraically closed, that is,
IsIntegrallyClosedIn k F — equivalently algebraicClosure k F = ⊥ — and let E be a further
commutative F-algebra. An element x of E algebraic over k then has the same minimal
polynomial over F as over k: the coefficients of minpoly F x are integral over k, because
that polynomial divides the monic polynomial (minpoly k x).map (algebraMap k F), and relative
algebraic closedness puts them back into k.
Consequently, for E a field, F⟮x⟯ / F and k⟮x⟯ / k have the same degree. This is the
mechanism behind the degree behaviour of a constant field extension: adjoining constants to F
costs exactly what adjoining them to k costs. More strongly, every separable extension
of k inside E is linearly disjoint from F, and a linearly independent family of separable
constants over k stays linearly independent over F. Linear disjointness also shows that the
compositum F · k' with a separable extension k' of k acquires no new separable constants: an
element of F · k' separable over k' already lies in k'.
Main results #
TauCeti.minpoly.map_algebraMap_of_isIntegrallyClosedIn:minpoly F xis the image ofminpoly k x.TauCeti.IntermediateField.finrank_adjoin_simple_eq_finrank_adjoin_simple_of_isIntegrallyClosedIn:[F⟮x⟯ : F] = [k⟮x⟯ : k].TauCeti.linearDisjoint_fieldRange_of_isIntegrallyClosedIn: a separable extension ofkinside a common overfield is linearly disjoint fromF.TauCeti.linearIndependent_algebraMap_comp_of_isIntegrallyClosedIn: a linearly independent family of separable elements stays linearly independent after extending scalars fromktoF.TauCeti.linearIndependent_algebraMap_comp_of_isIntegrallyClosedIn_of_isSeparable: a linearly independent family inFstays linearly independent after extending scalars fromkto a separable extensionk'.TauCeti.relfinrank_sup_adjoin_simple_eq_relfinrank_adjoin_simple_of_isIntegrallyClosedIn:[F · k' : k'(x)] = [F : k(x)]forx ∈ Fand finite separablek'/k.TauCeti.IntermediateField.eq_of_le_of_adjoin_le_of_isIntegrallyClosedIn: a finite separable extension ofkinsideEis determined by its compositum withF.TauCeti.mem_range_algebraMap_of_mem_adjoin_of_isSeparable_of_isIntegrallyClosedIn: an element of the compositumF · k'separable overk'lies ink'.
References #
- H. Stichtenoth, Algebraic Function Fields and Codes, 2nd ed., GTM 254, Springer, 2009,
Section III.6. This is the field theory behind the persistence of linear independence under a
constant field extension (Proposition 3.6.1(b)) and behind the determination of the constant
field of a constant field extension (Proposition 3.6.1(a)) and the degree identity
(Proposition 3.6.1(c)); it is stated here for an arbitrary
extension
F / kwithkrelatively algebraically closed, with no function field involved.
If k is relatively algebraically closed in F, then an element of an extension of F that
is algebraic over k has the same minimal polynomial over F as over k.
Without the hypothesis only the divisibility minpoly F x ∣ (minpoly k x).map (algebraMap k F)
holds; the content is that the coefficients of the left-hand factor, being integral over k and
lying in F, are constants.
If k is relatively algebraically closed in F, then adjoining an element algebraic over k
to F raises the degree by exactly as much as adjoining it to k does.
Linear disjointness from a separable extension #
A separable extension k' of a relatively algebraically closed field k is linearly
disjoint from F inside any common overfield E.
Consequently the compositum of F and k' inside E behaves like F ⊗[k] k': for finite
k' / k it has degree [k' : k] over F. This is the field-theoretic content of Stichtenoth,
Proposition 3.6.1(b), for separable constant field extensions.
A linearly independent family of separable elements over a relatively algebraically closed
field k remains linearly independent after extending scalars to F inside a common overfield.
For an algebraic function field and a separable constant field extension, this is Stichtenoth, Proposition 3.6.1(b).
Linear independence over k persists over a separable extension k' (Stichtenoth,
Proposition 3.6.1(b)): if k is relatively algebraically closed in F and k' / k is separable,
then a family of elements of F linearly independent over k stays linearly independent over
k' inside a common overfield E.
This is the companion of TauCeti.linearIndependent_algebraMap_comp_of_isIntegrallyClosedIn,
which extends scalars on the other side of the linearly disjoint pair F, k'.
Constants of the compositum #
A finite separable extension of a relatively algebraically closed field is determined by its
compositum with F: if K₀ ≤ K₁ are finite separable extensions of k inside E and the
compositum F · K₁ is contained in F · K₀, then K₀ = K₁.
Linear disjointness gives [F · Kᵢ : F] = [Kᵢ : k], so the two composita being equal forces the two
degrees over k to agree.
A separable constant of the compositum F · k' is a constant of k': if k is relatively
algebraically closed in F and k' / k is separable algebraic, then every element of the
compositum of F and k' inside a common overfield E that is separable over k' already lies
in k'.
For an algebraic function field and a separable constant field extension, this is the content of
Stichtenoth, Proposition 3.6.1(a), stated with separability of the constant in place of
perfectness of k; over a perfect k every constant is separable.
For k relatively algebraically closed in F, A/k finite separable, and E = A · F
(inside E), the degrees satisfy [E : A(x)] = [F : k(x)] for every x ∈ F.
This is the finite separable case of Stichtenoth, Algebraic Function Fields and Codes, second
edition, Proposition 3.6.1(c).
For the scalar-tower formulation with constantCompositum, see
TauCeti.finrank_over_adjoin_simple_eq_of_constantCompositum_eq_top in
TauCeti.FieldTheory.FunctionField.ConstantExtension.Degree.