Invertible manifold derivatives of composites #
If f has invertible manifold derivative at x and g has invertible manifold derivative at
f x, then g ∘ f has invertible manifold derivative at x. No differentiability hypothesis is
needed, since an invertible derivative forces differentiability
(mdifferentiableAt_of_isInvertible_mfderiv), and no finite-dimensionality or smoothness of the
manifolds is assumed.
Between manifolds modelled on finite-dimensional spaces of the same dimension over a complete
field, an injective manifold derivative is invertible (isInvertible_mfderiv_of_injective).
Conversely to the first statement, if the middle manifold is modelled on a finite-dimensional
space and the target model has the same dimension, and a composite of differentiable maps has
invertible manifold derivative, then so do both factors
(isInvertible_mfderiv_of_isInvertible_mfderiv_comp); neither completeness of the field nor
finite-dimensionality of the source or target model is assumed (the target is a quotient of the
middle space).
If the source is modelled on a finite-dimensional space over a complete field and the derivative
carries a tangent basis b onto a basis b', then it is the continuous linear equivalence mapping
b to b' (exists_coe_eq_mfderiv_of_basis), so it is invertible
(isInvertible_mfderiv_of_basis).
A composite of maps with invertible manifold derivatives at x and f x has invertible
manifold derivative at x.
Between manifolds modelled on finite-dimensional spaces of the same dimension over a complete field, an injective manifold derivative is invertible.
Between manifolds whose middle model is finite-dimensional and whose target model has the same dimension, if a composite of differentiable maps has invertible manifold derivative, then so do both factors. The source and target models need not be assumed finite-dimensional (the target is a quotient of the middle space), and the field need not be complete.
If the source is modelled on a finite-dimensional space over a complete field and the
derivative at x carries a basis b of the tangent space at x to a basis b' of the tangent
space at f x, then the derivative is a continuous linear equivalence mapping b to b'.
If the source is modelled on a finite-dimensional space over a complete field and the
derivative at x carries a basis b of the tangent space at x to a basis b' of the tangent
space at f x, then it is invertible.