Curvature of a disjoint union of Riemannian manifolds #
Let g₁ and g₂ be smooth Riemannian metrics on manifolds M and M' modelled on the same
space, and let g₁ ⊔ g₂ be the metric on the disjoint union M ⊕ M' which is g₁ on M and g₂
on M' (Bundle.ContMDiffRiemannianMetric.sumTangentSpace). The inclusions of M and M' into
M ⊕ M' are local Riemannian isometries, so every curvature quantity of g₁ ⊔ g₂ at a point of a
summand is that of the metric of the summand. In particular the scalar curvature of g₁ ⊔ g₂ is
Scal(g₁) on M and Scal(g₂) on M'.
Main results #
Bundle.ContMDiffRiemannianMetric.isLocalRiemannianIsometry_sumInlandBundle.ContMDiffRiemannianMetric.isLocalRiemannianIsometry_sumInr: the inclusions of the summands are local Riemannian isometries.Bundle.ContMDiffRiemannianMetric.scalarCurvature_sumTangentSpace_inlandBundle.ContMDiffRiemannianMetric.scalarCurvature_sumTangentSpace_inr: the scalar curvature of the disjoint union metric on each summand is that of the metric of the summand.
References #
- J. M. Lee, Introduction to Riemannian Manifolds, 2nd ed., Springer GTM 176 (2018), Chapter 2 (local isometries) and Proposition 7.6 (naturality of the curvature tensor).
The inclusion of M into M ⊕ M' is a local Riemannian isometry from g₁ to the disjoint
union of g₁ and g₂.
The inclusion of M' into M ⊕ M' is a local Riemannian isometry from g₂ to the disjoint
union of g₁ and g₂.
The scalar curvature of the disjoint union of metrics g₁ and g₂ at a point of M is the
scalar curvature of g₁ there.
The scalar curvature of the disjoint union of metrics g₁ and g₂ at a point of M' is the
scalar curvature of g₂ there.