Covariant differentiation commutes with the metric trace #
Let ∇ be a connection on the tangent bundle of a Riemannian manifold which is compatible with
the metric, and let b be a field of bilinear forms on the tangent spaces. The metric trace
tr_g b is then a function on the manifold whose derivative is the metric trace of the covariant
derivative of b:
d (tr_g b)(v) = ∑ᵢ (∇_v b)(eᵢ, eᵢ)
for every orthonormal basis eᵢ of the tangent space at the point. Since the metric is parallel,
the contraction against it commutes with covariant differentiation. This is the identity that
turns the contracted second Bianchi identity into 2 div Ric = d Scal, and more generally
computes the derivative of any metric trace of a covariant two-tensor.
The proof works in the chart-local frame Fᵢ and its metric-dual frame
Dᵢ = ∑ⱼ (G⁻¹)ᵢⱼ Fⱼ, where G is the Gram matrix of Fᵢ. Near the point,
tr_g b = ∑ᵢ b(Fᵢ, Dᵢ). Differentiating ⟪Dᵢ, Fⱼ⟫ = δᵢⱼ with the metric shows that the terms of
d (∑ᵢ b(Fᵢ, Dᵢ)) involving ∇Fᵢ and ∇Dᵢ cancel, which leaves ∑ᵢ (∇_v b)(Fᵢ, Dᵢ).
Main results #
CovariantDerivative.IsMetricCompatible.mvfderiv_bilinFormTrace: the derivative of the metric trace of a field of bilinear forms is the trace of its covariant derivative.
References #
- J. M. Lee, Introduction to Riemannian Manifolds, 2nd ed., Springer GTM 176 (2018), Ch. 4: covariant derivatives of tensor fields commute with contractions, and the metric is parallel.
Covariant differentiation commutes with the metric trace. For a connection compatible
with the metric and a field of bilinear forms b pairing sections differentiable at x to
functions differentiable at x, the derivative of the metric trace of b along v is the
metric trace of ∇_v b, computed in any orthonormal basis of the tangent space at x.