Integrability and Stokes formulas for symplectic area #
For a constant symplectic form ω, the primitive λₓ(v) = ½ ω(x, v) identifies the
symplectic area of a C² map on a closed rectangle with the integral of λ over its positively
oriented boundary (TauCeti.SymplecticForm.integral_fderiv_apply_prod_Icc), and the symplectic
area of a C² map on a closed annulus with the difference of its boundary actions.
The outer and inner circles are both parametrized counterclockwise on [-π, π], and the inner
action is subtracted. No extension across the inner disc is needed. Together with the
isoperimetric inequality for the boundary loops, this is the Stokes step used in energy decay
and removal of singularities for holomorphic curves.
For a loop x : [0, 1] → V, the integral of λ along it is the loop area
a(x) = ½ ∫₀¹ ω(x(t), x'(t)) dt (TauCeti.SymplecticForm.loopArea). If the bottom and top sides
of a map u on [a, b] × [0, 1] agree, so that each t ↦ u(s, t) is a loop, the rectangle
formula says that the symplectic area of u is a(u(b, ·)) - a(u(a, ·))
(TauCeti.SymplecticForm.integral_symplecticForm_fderiv_eq_loopArea_sub). In particular the loop
area of a closed loop is the symplectic area of the cone r x(t) bounding it
(TauCeti.SymplecticForm.integral_symplecticForm_fderiv_smul_eq_loopArea). Reparametrizing one
period of a 2π-periodic curve backwards as a loop on [0, 1] negates its area over [-π, π]
(TauCeti.SymplecticForm.loopArea_comp_sub_mul).
A square-integrable differential also gives an integrable symplectic area density, on any domain.
Pairing bounded loops with functions whose norms have vanishing mean over [0, 1] gives
integrals of the symplectic form that tend to zero
(TauCeti.SymplecticForm.tendsto_integral_apply_of_tendsto_integral_norm).
References #
- D. McDuff and D. Salamon, J-holomorphic Curves and Symplectic Topology, 2nd ed., AMS Colloquium Publications 52, 2012, Section 4.5.
A square-integrable differential has integrable symplectic area density.
Pairing with functions of vanishing mean norm. If the loops y_i are bounded by R and the
integrals over [0, 1] of the norms of the continuous d_i tend to 0, then so do the integrals
∫₀¹ ω(y_i(t), d_i(t)) dt.
Stokes' formula for symplectic area on a rectangle. If u is C² at every point of the
rectangle Icc a b ⊆ ℝ × ℝ, its symplectic area over the rectangle is the integral of the
primitive λₓ(v) = ½ ω(x, v) along the positively oriented boundary: the right side minus the
left side of t ↦ ½ ω(u, ∂t u), minus the top side minus the bottom side of
s ↦ ½ ω(u, ∂s u).
The symplectic area ½ ∫₀¹ ω(x(t), x'(t)) dt of a loop x : [0, 1] → V: the integral of the
primitive λₓ(v) = ½ ω(x, v) of ω along the loop. For a closed loop it is the symplectic area
of the cone r x(t) bounding it (SymplecticForm.integral_symplecticForm_fderiv_smul_eq_loopArea).
Instances For
A constant loop has zero symplectic area.
The loop area of a circle traversed backwards. If g is 2π-periodic, the loop
t ↦ g(θ₀ - 2πt) runs once through a period of g in the reverse direction, so its loop area
is minus the area ½ ∫_{-π}^{π} ω(g(θ), g'(θ)) dθ of g over one period.
The loop area of a circle traversed forwards. If g is 2π-periodic, the loop
t ↦ g(θ₀ + 2πt) runs once through a period of g, so its loop area is the area
½ ∫_{-π}^{π} ω(g(θ), g'(θ)) dθ of g over one period.
The loop area of a loop traversed backwards. If x is 1-periodic, the loop
t ↦ x(-t) has the opposite loop area.
The symplectic area of a cylinder. Let u be C² near [a, b] × [0, 1], with
u(s, 1) = u(s, 0) for s ∈ [a, b], so that each t ↦ u(s, t) is a loop. Then the symplectic
area of u over the rectangle is the area of the loop at s = b minus the area of the loop at
s = a.
The loop area is the area of a cap. For a loop x that is C² near [0, 1] with
x 1 = x 0, the symplectic area of the cone D(r, t) = r x(t) over [0, 1] × [0, 1], a disc
bounding x, is the loop area of x.
Stokes' formula for symplectic area on an annulus. The pullback area of a C² map is
the outer boundary action minus the inner boundary action for the primitive λₓ(v) = ½ ω(x, v).
This identity does not require any regularity on the inner disc or a holomorphicity hypothesis.