The Wirtinger inequality for a compatible triple #
Let ω be a symplectic form compatible with an almost complex structure J, and let
g(v, w) = ω(v, J w) be the associated metric. The g-area of the parallelogram spanned by two
vectors is the norm of their wedge product,
|v ∧ w|_g = √(g(v, v) g(w, w) - g(v, w)²).
The degree-two Wirtinger inequality says that ω calibrates g:
ω(v, w) ≤ |v ∧ w|_g, with equality for linearly independent v and w exactly when
w = a v + b J v with b > 0, that is, when the oriented plane (v, w) is a J-complex line
carrying its complex orientation. The proof is a Cauchy--Schwarz argument: ω(v, w) = g(J v, w),
the vector J v is g-orthogonal to v and has the same length, and the component w⊥ of w
orthogonal to the plane spanned by v and J v contributes nothing to ω(v, w) but increases
|v ∧ w|_g² by g(v, v) g(w⊥, w⊥). In fact g(v, w)² + ω(v, w)² ≤ g(v, v) g(w, w).
The arithmetic-geometric mean inequality gives the second link of the chain
ω(v, w) ≤ |v ∧ w|_g ≤ (g(v, v) + g(w, w)) / 2; the second inequality is an equality exactly
when the pair (v, w) is conformal (g(v, v) = g(w, w) and g(v, w) = 0), and the two together
are equalities exactly when w = J v. Applied to the partial derivatives of a map from a surface,
this is the pointwise chain energy density ≥ area density ≥ symplectic area density of
TauCeti.Geometry.Symplectic.JHolomorphic.Energy.Area, where the equality case of the whole
chain is TauCeti.SymplecticForm.stdComplexLineEnergyDensity_eq_two_mul_symplecticForm_iff.
Everything is pointwise linear algebra: no integrability of J or closedness of ω is involved.
Main declarations #
TauCeti.SymplecticForm.wedgeNorm: theg-norm|v ∧ w|_gof a wedge of two vectors.TauCeti.SymplecticForm.Compatible.sq_associatedBilinForm_add_sq_le:g(v, w)² + ω(v, w)² ≤ g(v, v) g(w, w).TauCeti.SymplecticForm.Compatible.apply_le_wedgeNorm: the Wirtinger inequalityω(v, w) ≤ |v ∧ w|_g.TauCeti.SymplecticForm.Compatible.apply_eq_wedgeNorm_iff_of_linearIndependent: its equality casew = a v + b J vwithb > 0.TauCeti.SymplecticForm.Compatible.two_mul_wedgeNorm_le:2 |v ∧ w|_g ≤ g(v, v) + g(w, w), with equality caseTauCeti.SymplecticForm.Compatible.two_mul_wedgeNorm_eq_ifffor conformal pairs.
References #
- D. McDuff and D. Salamon, J-holomorphic Curves and Symplectic Topology, 2nd ed., AMS Colloquium Publications 52, 2012, Lemma 2.2.1.
The norm |v ∧ w|_g of the wedge of two vectors for the associated metric
g = ω(·, J ·): the square root of the Gram determinant g(v, v) g(w, w) - g(v, w)². For a
compatible pair this is the g-area of the parallelogram spanned by v and w.
Instances For
The wedge norm is the square root of the Gram determinant of the associated metric.
The wedge norm is nonnegative.
The wedge of a vector with itself has norm zero.
The wedge of the zero vector with any vector has norm zero.
The wedge of any vector with the zero vector has norm zero.
The wedge norm is symmetric for a J-invariant form, whose associated metric is
symmetric.
Cauchy--Schwarz along a complex line. For a compatible pair, the squares of the
components g(v, w) and ω(v, w) = g(J v, w) of w along the orthogonal pair v, J v add up
to at most g(v, v) g(w, w).
For a compatible pair, the square of the wedge norm is the Gram determinant
g(v, v) g(w, w) - g(v, w)².
For a compatible pair, the wedge norm is positive exactly for linearly independent pairs.
The wedge of v with J v has norm g(v, v): the pair (v, J v) is g-orthogonal and its
two vectors have the same length.
For a compatible pair, |ω(v, w)| is at most the wedge norm |v ∧ w|_g.
The Wirtinger inequality. A symplectic form compatible with J calibrates the associated
metric: ω(v, w) ≤ |v ∧ w|_g.
The equality case of the Wirtinger inequality for a nonzero first vector: ω(v, w) equals
|v ∧ w|_g exactly when w lies in the closed half of the complex line through v on the side
of J v, that is, w = a v + b J v with b ≥ 0.
The equality case of the Wirtinger inequality. For linearly independent v and w,
ω(v, w) = |v ∧ w|_g exactly when w = a v + b J v with b > 0: the oriented plane (v, w) is a
J-complex line with its complex orientation.
Area is at most energy. For a compatible pair,
2 |v ∧ w|_g ≤ g(v, v) + g(w, w).
The equality case of 2 |v ∧ w|_g ≤ g(v, v) + g(w, w): it holds exactly for conformal pairs,
those with g(v, v) = g(w, w) and g(v, w) = 0.