The Zariski topology of equations over groups #
The Zariski topology on tuples in a group receiving coefficients from G is generated by
complements of solution sets of systems of equations over G. Thus every algebraic set is
closed, whether or not the coefficient group or the target group is a domain. A tuple whose
coordinates are coefficients is a closed point. Word maps are continuous because substitution
pulls an equation back to an equation.
The topology is attached to the coefficient homomorphism: different choices of coefficients can give different closed sets on the same underlying group of points.
When the target is a domain over the coefficients and the coefficient image is nontrivial, commutator equations make finite unions algebraic. In that case all closed sets are algebraic and the closure of a set is the solution set of its ideal of vanishing equations. The nontrivial-image condition makes the empty set algebraic; it can fail even for injective coefficient maps when the coefficient group is trivial.
Without any domain hypothesis, the closure of an irreducible set Y is still the algebraic set
V_H(I_H(Y)), so every irreducible closed set is algebraic.
References #
- G. Baumslag, A. Myasnikov, V. Remeslennikov, Algebraic geometry over groups I. Algebraic sets and ideal theory, J. Algebra 219 (1999), §3.2, Theorem 3 and Lemma 11; §3.6, Proposition 10.
The Zariski topology generated by the complements of algebraic sets over G.
Instances For
The equations in unionEquations S T are the commutators of one equation from each
system, conjugated by coefficients.
A map into a Zariski space is continuous exactly when every algebraic set has closed preimage. This characterization does not require a domain or nontrivial coefficients.
Surjective coefficients make every point closed, hence the Zariski topology is T1.
Over a domain with a nontrivial coefficient image, the generated closed sets are exactly the algebraic sets. The nontrivial-image condition is needed for the empty closed set.
Over a domain with a nontrivial coefficient image, the Zariski closure is obtained by imposing all equations that vanish on the set.
The Zariski closure of an irreducible set is the algebraic set cut out by its ideal. No domain hypothesis is needed.
Every irreducible Zariski closed set is algebraic: it is cut out by its ideal.