Even Clifford elements in dimension one #
Every even element of a rank-one Clifford algebra is the image of a scalar, over any field, including one of characteristic two. The corresponding statement for units follows from the unit-lifting lemma for a homomorphism out of a group with zero.
The scalar calculation follows the standard Clifford algebra argument; see H. B. Lawson and M.-L. Michelsohn, Spin Geometry (1989), Chapter I, §2.
Main results #
CliffordAlgebra.exists_eq_algebraMap_of_mem_even_of_finrank_eq_one: every even element is a scalar in dimension one.CliffordAlgebra.exists_eq_unitsMap_algebraMap_of_mem_even_of_finrank_eq_one: every even unit comes from a unit of the base field.
theorem
CliffordAlgebra.exists_eq_algebraMap_of_mem_even_of_finrank_eq_one
{K : Type u}
{V : Type v}
[Field K]
[AddCommGroup V]
[Module K V]
(Q : QuadraticForm K V)
(hV : Module.finrank K V = 1)
(y : CliffordAlgebra Q)
(hy : y ∈ even Q)
:
∃ (a : K), y = (algebraMap K (CliffordAlgebra Q)) a
In dimension one, every even Clifford element equals the image of a scalar, over any field.
theorem
CliffordAlgebra.exists_eq_unitsMap_algebraMap_of_mem_even_of_finrank_eq_one
{K : Type u}
{V : Type v}
[Field K]
[AddCommGroup V]
[Module K V]
(Q : QuadraticForm K V)
(hV : Module.finrank K V = 1)
(x : (CliffordAlgebra Q)ˣ)
(hx : ↑x ∈ even Q)
:
∃ (a : Kˣ), x = (Units.map ↑(algebraMap K (CliffordAlgebra Q))) a
In dimension one, every even Clifford unit equals the image of a unit of the base field.