Rank-two dyadic blocks are u^{(2)}(2^k) or v^{(2)}(2^k) #
Let A be a finite quadratic module and K ≥ 1. Suppose x, y ∈ A are killed by 2^K, their
quadratic values q(x) and q(y) are killed by 2^K, and their pairing b(x, y) has exact order
2^K. Then the subgroup ⟨x, y⟩ they generate, with the restricted form, is isometric to one of
Nikulin's rank-two dyadic generators u^{(2)}(2^K) or v^{(2)}(2^K). In particular it is
nondegenerate, so it splits off orthogonally from A. This is the rank-two summand in Nikulin's
decomposition of a nondegenerate 2-primary finite quadratic module: an element x of maximal
order 2^K either generates a nondegenerate cyclic summand q_θ^{(2)}(2^K), or 2^{K-1} b(x, x)
vanishes, and then an element y of 2-power order with 2^{K-1} b(x, y) ≠ 0 either generates
a cyclic summand or, together with x, satisfies the hypotheses above.
Write q(x) = a / 2^K, q(y) = b / 2^K and b(x, y) = u / 2^K with a, b, u ∈ ℤ/2^K and u odd,
so that
q(m x + n y) = (a m² + u m n + b n²) / 2^K.
The classification is then the normal form of the binary form a m² + u m n + b n² over
ℤ/2^K, and it is decided by the parities of a and b.
- If
ais even, the form has an isotropic vector(m₀, 1), and completing it to a hyperbolic pair givesu^{(2)}(2^K), whereq(m, n) = mn / 2^K. The case of evenbis symmetric. - If
aandbare both odd, the form represents1at a vector(2j, 1), and a second vector can be adjusted to value1and pairing1with it, givingv^{(2)}(2^K), whereq(m, n) = (m² + mn + n²) / 2^K.
Each equation to be solved is reduced to a value of s ↦ 2cs² + us with u odd. That map is a
bijection of ℤ/2^K, because (2cs² + us) - (2ct² + ut) = (s - t)(2c(s + t) + u) and
2c(s + t) + u is a unit, 2 being nilpotent in ℤ/2^K; this replaces Hensel's lemma.
For K = 1 the hypotheses say that x and y are 2-torsion with b(x, x) = b(y, y) = 0 and
b(x, y) = 1/2, and the conclusion recovers, for the subgroup ⟨x, y⟩, the classification of
nondegenerate alternating forms on a Klein four-group in
TauCeti.LinearAlgebra.FiniteBilinearModule.Dyadic.KleinFour.
Main results #
TauCeti.FiniteQuadraticModule.nonempty_isometry_dyadicU_or_dyadicV_restrict_zmultiples_sup: the subgroup generated by suchxandyis isometric tou^{(2)}(2^K)orv^{(2)}(2^K).TauCeti.FiniteQuadraticModule.isNondegenerate_restrict_zmultiples_sup: that subgroup is nondegenerate.
References #
- V. V. Nikulin, Integral symmetric bilinear forms and some of their applications, Proposition 1.8.1.
- C. T. C. Wall, Quadratic forms on finite groups, and related topics, Topology 2 (1963), 281–298.
Transport to a finite quadratic module #
The classification #
Rank-two dyadic blocks. If x, y, q(x), and q(y) are all killed by 2^{k+1}, and
2^k b(x, y) ≠ 0, then the subgroup generated by x and y, with the restricted form, is
isometric to u^{(2)}(2^{k+1}) or to v^{(2)}(2^{k+1}).
Under the hypotheses of
TauCeti.FiniteQuadraticModule.nonempty_isometry_dyadicU_or_dyadicV_restrict_zmultiples_sup, the
subgroup generated by x and y is nondegenerate, so
TauCeti.FiniteQuadraticModule.restrictProdOrthogonalComplementIsometry splits it off A.