Documentation

TauCeti.LinearAlgebra.IntegralLattice.Neighbor.Hyperbolic

Neighbors become isometric after adding a hyperbolic plane #

Let L be an even lattice, p a positive integer and v ∈ L a vector whose norm is divisible by 2p², such that some lattice vector pairs with v coprimely to p. Then L ⊕ U ≅ L.neighbor p v ⊕ U, where U is the hyperbolic plane.

Write M = L.neighbor p v, b = v / p ∈ M and e, f for the standard isotropic basis of U. The vector z = p (b + e - (b · b / 2) f) of L ⊕ U is primitive and isotropic, and its orthogonal complement modulo z is identified with M by x + α e + β f ↦ x - α b. Choosing y ∈ L ⊕ U with z · y = 1 and correcting it to an isotropic vector, the plane spanned by z and y is a copy of U whose orthogonal complement is a copy of M. Assembled, this is an explicit rational isometry of M ⊕ U onto L ⊕ U carrying the integral carriers onto each other.

In particular two even unimodular lattices that are neighbors become isometric after adding U, although they need not be isometric themselves; this is how cancellation fails over ℤ.

Main results #

References #

Neighbors become isometric after adding a hyperbolic plane. Let L be even and let v ∈ L have norm divisible by 2p², with some w ∈ L pairing with v coprimely to p. Then L ⊕ U and L.neighbor p v ⊕ U are isometric, where U is the hyperbolic plane.