Nilpotence of upper-unitriangular matrix groups #
For a ring R, filter U_n(R) by requiring the entries on the first r - 1
superdiagonals to vanish. Multiplication of matrices supported at least r and s
superdiagonals above the diagonal is supported at least r + s superdiagonals above it. This
gives the central-series estimate
[U^r, U^s] ⊆ U^(r+s).
The first term is all of U_n(R), while the n-th term is trivial. Hence U_n(R) is
nilpotent, and therefore solvable, over every ring.
Main declarations #
TauCeti.UpperUnitriangularGroup.superdiagonalSubgroup: the subgroupU^rwhose firstr - 1superdiagonals vanish.TauCeti.UpperUnitriangularGroup.superdiagonalSubgroup_antitone: the filtration is decreasing.TauCeti.UpperUnitriangularGroup.commutator_superdiagonalSubgroup_le: the central-series estimate[U^r, U^s] ≤ U^(r+s).TauCeti.UpperUnitriangularGroup.instIsNilpotent: upper-unitriangular matrix groups are nilpotent.
References #
- T. A. Springer, Linear Algebraic Groups, §2.4.
- J. C. Jantzen, Representations of Algebraic Groups, I.2.
This is the nilpotence input for Layer 5, "Lie--Kolchin; solvable groups", of the ReductiveGroups roadmap. Combined with the upper-unitriangular embedding characterization, it gives the implication from unipotence to solvability.
The subgroup U^r of upper-unitriangular matrices whose entries below the r-th
superdiagonal vanish. Thus U^1 = U_n, and U^n = 1 for n × n matrices.
Equations
- One or more equations did not get rendered due to their size.
Instances For
Membership in U^r means that the matrix differs from the identity only on the r-th and
higher superdiagonals.
The superdiagonal filtration is decreasing: requiring more initial superdiagonals to vanish gives a smaller subgroup.
The first superdiagonal subgroup is the whole upper-unitriangular group.
Once the filtration index reaches the matrix size, the superdiagonal subgroup is trivial.
Commutators add filtration degrees: [U^r, U^s] ≤ U^(r+s).
Upper-unitriangular matrices over every finite linearly ordered index type form a nilpotent group over every ring.