The determinant of the pencil S⁻¹ - X #
For an invertible square matrix S over a commutative ring and any X, the determinant of the
pencil S⁻¹ - X is expressible in S and X themselves: multiplying through by det S clears
the inverse, and Sylvester's determinant identity turns what is left into det (1 - X * S). The
determinant of the inverse pencil follows, once the pencil is itself invertible.
Nothing here needs an order or a norm on the ring. Writing the perturbation as a scaled matrix
c • Θ gives the scale form of the matrix pencil carried by an exponential weight
exp (-trace ((S⁻¹ - c • Θ) * A) / 2), where S is a scale matrix and c • Θ the tilt of a trace
statistic; the positivity of that form, which does need an order, is in
TauCeti/Analysis/Matrix/Sqrt.lean.
Main results #
Matrix.det_mul_det_inv_sub— the determinant of the pencil, in the parametersSandX;Matrix.det_nonsing_inv_inv_sub— the determinant of the inverse pencil;Matrix.det_mul_det_inv_sub_smulandMatrix.det_nonsing_inv_inv_sub_smul— the same two identities for a scaled perturbationc • Θ.
The determinant of the pencil S⁻¹ - X, in the parameters S and X themselves.
Only the invertibility of S is used.
The determinant of the scale pencil S⁻¹ - c • Θ, in the parameters S and Θ themselves.
The determinant of the inverse scale pencil. This is the determinant of the scale matrix
carried by an exponential weight exp (-trace ((S⁻¹ - c • Θ) * A) / 2).