Functions continuous on a compact set are essentially bounded #
A function continuous on a compact set K is bounded there, so it lies in L^∞(μ.restrict s) for
every measurable s ⊆ K (ContinuousOn.memLp_top_restrict_of_subset_isCompact). Allowing s ⊊ K
covers the usual case of an open interval (a, b) inside the compact interval [a, b]. This is the
continuous counterpart of Mathlib's MonotoneOn.memLp_top, and the restricted-measure counterpart
of Continuous.memLp_top_of_hasCompactSupport.
On a compact space with a measure that is finite on compact sets, every continuous function lies in
every Lᵖ, so for a finite exponent p ≠ 0 its Lᵖ seminorm is the integral
(∫ ‖f‖ ^ p dμ) ^ (1 / p) (Continuous.eLpNorm_eq_integral_rpow_norm).
A function continuous on a compact set K is essentially bounded on every measurable
s ⊆ K.
The Lᵖ seminorm of a continuous function on a compact space, for a finite exponent p ≠ 0
and a measure finite on compact sets, as an integral: ‖f‖_{Lᵖ} = (∫ ‖f‖ ^ p dμ) ^ (1 / p).