Continuous functions are a.e. strongly measurable for inner regular measures #
Mathlib's ContinuousOn.aestronglyMeasurable and Continuous.aestronglyMeasurable read almost
everywhere strong measurability of a continuous function off second countability of its source or
target. This file gives the alternative source of separability: inner regularity of the measure.
If μ is inner regular with respect to compact sets on measurable sets of finite measure
(MeasureTheory.Measure.InnerRegularCompactLTTop), as every regular measure is (for instance the
Haar measure MeasureTheory.Measure.addHaar of a locally compact group), then up to a null set each
such set is a countable union of compact sets, whose images under a continuous function are
separable.
The main application is to integrands f x • g x with f integrable and g continuous, such as
the orbits g ↦ f g • π g v integrated in the integrated form of a strongly continuous group
representation. On a locally compact group that is not σ-compact a Haar measure is not σ-finite,
and a continuous function need not be a.e. strongly measurable on the whole group; but an
integrable f lives on a σ-finite set, and there the inner regular case applies.
Main statements #
ContinuousOn.aestronglyMeasurable_of_measure_ne_top: a function continuous on a measurable set of finite measure is a.e. strongly measurable for the restriction ofμto that set.Continuous.aestronglyMeasurable_of_sigmaFinite: a continuous function is a.e. strongly measurable for a σ-finite inner regular measure.MeasureTheory.AEFinStronglyMeasurable.aestronglyMeasurable_smul: the productf • gof an a.e. finitely strongly measurablef(for instance an integrable one) and a continuousgis a.e. strongly measurable.
For a measure that is inner regular with respect to compact sets on sets of finite measure, a
function continuous on a measurable set s of finite measure is a.e. strongly measurable for the
restriction of the measure to s.
A continuous function is a.e. strongly measurable for a σ-finite measure that is inner regular
with respect to compact sets on sets of finite measure. Compare Continuous.aestronglyMeasurable,
which asks for second countability of the source or the target instead.
The product of an a.e. finitely strongly measurable function f, for instance an integrable
one, and a continuous function g is a.e. strongly measurable, for a measure that is inner regular
with respect to compact sets on sets of finite measure. No σ-finiteness of the measure and no
second countability is needed: f vanishes outside a σ-finite set, on which g is a.e. strongly
measurable by Continuous.aestronglyMeasurable_of_sigmaFinite.