Lebesgue integrals of truncations #
The truncations min f M of a function f : α → ℝ≥0∞ at finite levels M increase to f, so by
monotone convergence their Lebesgue integrals tend to that of f as M → ∞. Neither f nor its
integral needs to be finite.
Cutting the truncations off outside the sets spanning a σ-finite measure also makes every
power of them integrable, so a bound on ∫⁻ φ ^ q proved for all φ ≤ G with ∫⁻ φ ^ q
finite passes to ∫⁻ G ^ q. This is the usual way to divide an inequality by a power of the
quantity being estimated.
Main statements #
TauCeti.tendsto_lintegral_min_atTop:∫⁻ x, min (f x) M ∂μ → ∫⁻ x, f x ∂μasM → ∞.TauCeti.lintegral_enorm_rpow_eq_setLIntegral: theq-th power integral of a truncation to a measurable set is the truncated integral.TauCeti.lintegral_rpow_le_of_forall_le: a bound on∫⁻ φ ^ qfor the measurableφ ≤ Gwith∫⁻ φ ^ qfinite is a bound on∫⁻ G ^ q.
Integrals of truncations. If f : α → ℝ≥0∞ is almost everywhere measurable, then the
integrals of its truncations min f M tend to the integral of f as the finite level M tends
to ∞, whether or not that integral is finite.
The q-th power integral of a truncation of f is a truncated integral of ‖f‖ ^ q.
Monotone convergence through truncations. For a σ-finite measure μ and 0 < q, if
∫⁻ φ ^ q ≤ C for every measurable φ ≤ G with ∫⁻ φ ^ q finite, then ∫⁻ G ^ q ≤ C.
The truncations min G N, cut off outside the N-th spanning set of μ, have finite
∫⁻ φ ^ q and increase to G.