The continued L-function of a cancelling weight does not vanish on Re s ≥ 1 #
Let χ be a unitary ideal weight of a number field K with cancellation
(TauCeti.HasCancellation χ), so that its continued L-function
TauCeti.continuedLFunctionOfWeight χ is holomorphic on Re s > 1 - 1 / [K : ℚ]. On Re s > 1
it is the L-series of χ, which does not vanish there because of its Euler product. This file
proves that it has no zeros on the line Re s = 1 either, under a hypothesis on the pointwise
square χ ^ 2.
The classical 3-4-1 argument compares χ with χ ^ 2: for σ > 1,
1 ≤ ‖ζ_K(σ) ^ 3 L(χ, σ + it) ^ 4 L(χ ^ 2, σ + 2it)‖. A zero of L(χ, ·) at 1 + it
outweighs the simple pole of ζ_K at 1, provided the L-series of χ ^ 2 continues
continuously to 1 + 2it (TauCeti.UnitaryIdealWeight.ne_zero_of_eqOn_LSeries). The square is
handled in two ways:
- if
χ ^ 2also has cancellation, its own continued L-function supplies the continuation, and the continued L-function ofχhas no zero onRe s ≥ 1; - if
χ ^ 2is a norm twistI ↦ N(I) ^ (u * I)on its good ideals (as for a quadratic character, whereu = 0), itsL-series is a translate of a Dedekind zeta function with finitely many Euler factors deleted. That translate is continuous away from its pole at1 + u * I, which leaves only the points = 1 + (u / 2) * Iuncovered.
The cases are not exhaustive in general. A character-family argument supplies cancellation for
the nondegenerate members of its family. For a quadratic character the excluded point s = 1
needs a different argument, since there L(χ ^ 2, ·) has a pole.
Main results #
TauCeti.continuedLFunctionOfWeight_ne_zero_of_one_lt_re: nonvanishing onRe s > 1, for every unitary weight.TauCeti.continuedLFunctionOfWeight_ne_zero_of_hasCancellation_sq: if bothχandχ ^ 2have cancellation, the continued L-function ofχhas no zeros onRe s ≥ 1.TauCeti.continuedLFunctionOfWeight_ne_zero_of_isNormTwistOnGood_sq: ifχhas cancellation andχ ^ 2is a norm twist with parameteruon its good ideals, there are no zeros onRe s ≥ 1other than possibly1 + (u / 2) * I.TauCeti.continuedLFunctionOfWeight_ne_zero_of_isTrivialOnGood_sq: the caseu = 0, for weights whose square is trivial on its good ideals.
References #
- H. Davenport, Multiplicative Number Theory, Chapter 4.
- The case analysis on the square follows Mathlib's
Mathlib/NumberTheory/LSeries/Nonvanishing.lean(Michael Stoll and David Loeffler), whereDirichletCharacter.LFunction_ne_zero_of_re_eq_oneproves the analogous statement for DirichletL-functions.
No zeros to the right of 1. For every unitary weight χ, with or without cancellation,
the continued L-function of χ does not vanish on Re s > 1: there it is the L-series of χ,
an absolutely convergent Euler product.
Nonvanishing when the square also cancels. If a unitary weight χ and its pointwise
square χ ^ 2 both have cancellation, the continued L-function of χ has no zeros on the closed
half-plane Re s ≥ 1.
Nonvanishing when the square is a norm twist on its good ideals. Let χ be a unitary
weight with cancellation whose pointwise square agrees with I ↦ N(I) ^ (u * I) on its good
ideals. Then the continued L-function of χ has no zeros on Re s ≥ 1 except possibly at
s = 1 + (u / 2) * I, where the L-series of χ ^ 2 has its pole at 2s - 1 = 1 + u * I.
Nonvanishing when the square is trivial on its good ideals, as for a quadratic character.
If a unitary weight χ has cancellation and χ ^ 2 takes the value 1 on its good ideals, the
continued L-function of χ has no zeros on Re s ≥ 1 except possibly at s = 1.