Choosing a Hasse derivative of Roth's auxiliary polynomial #
In the proof of Roth's theorem, an integer auxiliary polynomial P vanishes to a high index at
the diagonal point (α, …, α), while Roth's index estimate shows that its index at a tuple β of
good rational approximations of α is small. The final step needs a polynomial that does not
vanish at β at all. It is obtained as a Hasse derivative Q = ∂^d P, where d is a jet of P
at β of minimal weight. Since ∂^d lowers indices by at most the weight of d, the index of
Q at the diagonal point is still large, and the coefficients of Q are at most 2 ^ ∑ᵢ rᵢ
times those of P, where the rᵢ bound the partial degrees of P.
The value Q(β) is then a nonzero rational number which is bounded from above using the large
index of Q at the diagonal point, and from below by the denominators of β. Comparing the two
bounds yields the contradiction which proves Roth's theorem.
Main results #
TauCeti.exists_roth_hasseDeriv: the choice ofQmade byMvPolynomial.exists_hasseDeriv_eval_ne_zero, with the parameters of the proof of Roth's theorem. An index at least(n / 2) (1 - ε)ataand an index at most5 n ε / 2atbleave the derivative an index at least(1 / 2 - 3 ε) nata, and coefficients at mostexp (C₁ ∑ᵢ rᵢ)with∑ᵢ rᵢ ≤ 2 D / Lbecome coefficients at mostexp (4 C₁ D / L).
References #
- L. Pottmeyer, Diophantine Approximation (2022), §3.5, Lemma 3.5.7.
Pottmeyer, Lemma 3.5.7. The choice of a nonvanishing Hasse derivative of Roth's
auxiliary polynomial. Let P be an integer polynomial in n variables with partial degrees
degreeOf i P ≤ r i, where ∑ᵢ rᵢ ≤ 2 D / L, and with coefficients of absolute value at most
exp (C₁ ∑ᵢ rᵢ), where C₁ ≥ log 2. Let 0 ≤ ε. If the index of P is at least
(n / 2) (1 - ε) at a and at most 5 n ε / 2 at b, then some Hasse derivative
Q = ∂^d P does not vanish at b, has index at least (1 / 2 - 3 ε) n at a, has partial
degrees at most r i, and has coefficients of absolute value at most exp (4 C₁ D / L).