The left detour in Newman's contour argument #
Newman's Tauberian theorem integrates a function g holomorphic on an open set Ω containing
the closed half-plane 0 ≤ re z against dz / z over a closed contour around 0: the right
semicircle of radius R, parametrized counterclockwise from -R * I to R * I by
circleMap 0 R on [-π/2, π/2], followed by a detour back to -R * I through the left
half-plane, close enough to the imaginary axis to stay inside Ω.
The detour used here is the parabolic arc newmanDetour R δ, parametrized on [-1, 1] by
s ↦ -δ (1 - s²) - R s I. It runs from R * I to -R * I; for R ≥ 0 and δ > 0 it lies in
the strip -δ ≤ re z ≤ 0, |im z| ≤ R, and meets the imaginary axis only at its endpoints. This
file proves:
exists_convex_newmanDetour_subset: by compactness of the segment[-R * I, R * I], for someδ > 0the right semicircle and the detour lie in an open convex subset ofΩ;integral_right_semicircle_add_integral_newmanDetour: Cauchy's integral formula for the closed contour formed by the right semicircle and the detour, forgholomorphic on such a convex set: the two integrals ofg z / zadd up to2πi g 0;integral_left_semicircle_eq_integral_newmanDetour: the detour may replace the left semicircle in the integral ofg z / z, forgholomorphic on a convex set containing both;tendsto_integral_newmanDetour_mul_cexp,tendsto_integral_newmanDetour_mul_kernel: forGcontinuous on the detour, the detour integral ofGagainst Newman's kernelexp (T z) (1 + z² / R²) / ztends to0asT → ∞, by dominated convergence:exp (T z) → 0on the interior of the detour, wherere z < 0, and the endpoints have measure zero;intervalIntegrable_newmanDetour_mul_kernel: the detour integrand of a function continuous along the detour against Newman's kernel is interval integrable.
The deformation identities split g z / z into the removable-singularity quotient
dslope g 0, which has a primitive on the convex set, and the polar part g 0 / z, whose
integral over each of the three arcs is g 0 * π i, since dz / z integrates to π i there
(the general splitting is
TauCeti.Contour.integral_mul_div_eq_of_hasDerivAt_dslope).
References #
- D. J. Newman, Simple analytic proof of the prime number theorem, Amer. Math. Monthly 87 (1980), 693–696.
- D. Zagier, Newman's short proof of the prime number theorem, Amer. Math. Monthly 104 (1997), 705–708.
Newman's left detour. The parabolic arc s ↦ -δ (1 - s²) - R s I, which on [-1, 1]
runs from R * I to -R * I; for R, δ ≥ 0 it stays in the strip -δ ≤ re z ≤ 0,
|im z| ≤ R.
Instances For
The real part of the detour, -δ (1 - s²).
The imaginary part of the detour, -R s.
The detour starts at R * I.
The detour ends at -R * I.
The velocity of the detour is 2 δ s - R I.
The detour is continuous.
For R ≠ 0 and δ ≠ 0 the detour avoids 0.
The detour inside the continuation domain. If Ω is open and contains the closed
half-plane 0 ≤ re z, then for some δ > 0 the right semicircle of radius R and the detour
newmanDetour R δ lie in a common open convex subset of Ω.
Cauchy's formula for Newman's contour. Let g be holomorphic on an open convex set U
containing the right semicircle of radius R > 0 and the detour newmanDetour R δ with
δ > 0. Then the integral of g z / z over the right semicircle, counterclockwise from
-R * I to R * I, plus its integral over the detour, back from R * I to -R * I through the
left half-plane, is 2πi g 0. Both integrals include the velocity of their parametrization.
The detour replaces the left semicircle. If g is holomorphic on an open convex set U
containing the left semicircle of radius R > 0 and the detour newmanDetour R δ with δ > 0,
then the integrals of g z / z over the left semicircle, counterclockwise from R * I to
-R * I, and over the detour, which has the same endpoints, agree.
The detour contribution vanishes in the limit. If w is continuous on the detour
newmanDetour R δ with δ > 0, then ∫ w(z) exp (T z) dz over the detour tends to 0 as
T → ∞: the integrand is dominated by |w(z) dz|, and exp (T z) → 0 wherever re z < 0,
which holds except at the two endpoints.
The detour contribution in Newman's argument vanishes in the limit. If G is continuous
on the detour newmanDetour R δ with R, δ > 0, then the detour integral of G against Newman's
kernel exp (T z) (1 + z² / R²) / z tends to 0 as T → ∞.
For R, δ > 0, the detour integrand of a function w continuous along the detour
newmanDetour R δ against Newman's kernel exp (T z) (1 + z² / R²) / z is interval integrable
on [-1, 1].