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TauCeti.NumberTheory.ModularForms.LevelOne.FundamentalDomainBoundary.ArcExcisionMeasure

The excision leaves the arc's full length in the limit #

The valence formula integrates over the fundamental-domain boundary with the integrand excised within ε of the elliptic points. On the arc the excised integral turns out to be a constant multiple of the length of the surviving parameter set, so its ε → 0 limit is governed by that length alone.

This file supplies both halves. The arc runs once around a π/3 sector of the unit circle, so it meets each excision centre at most once (injOn_fdBoundary_arc), and TauCeti.Contour.tendsto_intervalIntegral_excisionIndicator applies with the whole length 2. The constant is the contour's own logarithmic derivative, which on the arc is (π/6)·I (logDeriv_fdBoundary_arc), so the excised integral tends to (π/3)·I.

References #

Main results #

The excision leaves the arc's full length in the limit. Deleting from [1, 3] the times at which the boundary comes within ε of one of finitely many centres costs no length as ε → 0⁺: the surviving length tends to 2.

theorem TauCeti.ModularForm.intervalIntegral_excised_logDeriv_fdBoundary_arc (H : ℝ) (S : Finset ℂ) (ε : ℝ) :
(∫ (t : ℝ) in 1..3, if ∃ s ∈ S, ‖fdBoundary H t - s‖ ≤ ε then 0 else logDeriv (fdBoundary H) t) = ↑(Real.pi / 6) * Complex.I * ↑(∫ (t : ℝ) in 1..3, if ∃ s ∈ S, ‖fdBoundary H t - s‖ ≤ ε then 0 else 1)

The excised arc integral of the contour's own logarithmic derivative. On the arc logDeriv (fdBoundary H) is the constant (π/6)·I (logDeriv_fdBoundary_arc), so the excised integral is that constant times the surviving length.

The arc's excised logarithmic-derivative integral tends to (π/3)·I. Combining the constant value on the arc with the surviving length's limit 2.