The Galois group of a multiquadratic field is (ℤ/2)ⁿ #
Over a field K in which 2 ≠ 0, a multiquadratic field M = K(rootᵢ : i) (with
rootᵢ ^ 2 = dᵢ ∈ K) is Galois (TauCeti.NumberTheory.Multiquadratic.Galois.Basic). Each
automorphism sends every generator to ± rootᵢ, so it is determined by a sign pattern ι → ℤ/2;
this assignment is an injective group homomorphism. When the radicands are square-class independent
the degree is 2ⁿ (TauCeti.NumberTheory.Multiquadratic.Degree), so counting forces the
homomorphism to be an isomorphism: Gal(M/K) ≃ (ℤ/2)ⁿ.
Main results #
TauCeti.Multiquadratic.signHom: the injective sign-pattern homomorphismGal(M/K) →* (ℤ/2)ⁿ.TauCeti.Multiquadratic.galoisGroupEquiv: for square-class independent radicands, the explicit isomorphismGal(M/K) ≃* Multiplicative (ι → ℤ/2).TauCeti.Multiquadratic.aut_nontrivial: under square-class independence over a nonempty index type,Gal(M/K)is nontrivial.TauCeti.Multiquadratic.card_aut_adjoin_range: the cardinality reading|Gal(M/K)| = 2^|ι|of that isomorphism.TauCeti.Multiquadratic.nonempty_mulEquiv_gal_definingPolynomial: the same group read as the Galois groupPolynomial.Galof the defining polynomial∏ᵢ (X² - dᵢ).
Provenance #
Generalised from kim-em/erdos-unit-distance, the formalization of L. Alpöge's disproof of the uniform-constant Erdős unit-distance conjecture, where the sign-change automorphisms of one concrete multiquadratic field were analysed; here the construction is carried out for an arbitrary such tower.
The sign pattern of an automorphism: 0 where it fixes a generator and 1 otherwise.
When gen root i ≠ -gen root i, the 1 case says that the automorphism negates the generator.
Equations
- TauCeti.Multiquadratic.signPattern root σ i = if σ (TauCeti.Multiquadratic.gen root i) = TauCeti.Multiquadratic.gen root i then 0 else 1
Instances For
An automorphism acts on each generator by the corresponding sign.
Read the sign pattern off a generator-wise sign. If σ (gen root i) = ε • gen root i
with ε = ±1 (in ℤ) and d i ≠ 0, then signPattern root σ i is 0 when ε = 1 and 1
when ε = -1. This bridges a generator-wise sign — for instance a Frobenius acting on √dᵢ by
a Legendre symbol (NumberField.isArithFrobAt_apply_sqrt) — to the (ℤ/2)ⁿ
identification, so it composes with TauCeti.Multiquadratic.galoisGroupEquiv_apply.
Two automorphisms with the same sign pattern are equal.
The sign is 0 exactly where the automorphism fixes the generator.
The sign is 0 iff the automorphism fixes the generator.
The sign is 1 where the automorphism negates a generator that differs from its negation.
The sign is 1 iff the automorphism negates a generator that differs from its negation.
Pointwise composition rule for sign patterns.
The sign pattern is additive: it is a group homomorphism to ι → ℤ/2.
The Galois group of M / K maps to the sign patterns (ℤ/2)ⁱ.
Equations
- One or more equations did not get rendered due to their size.
Instances For
Evaluation rule for signHom: it is the multiplicative form of signPattern.
The sign-pattern homomorphism is injective.
For square-class independent radicands, the Galois group of a multiquadratic field is
(ℤ/2)ⁿ.
Equations
- TauCeti.Multiquadratic.galoisGroupEquiv hroot hindep = MulEquiv.ofBijective (TauCeti.Multiquadratic.signHom root hroot) ⋯
Instances For
A multiquadratic field over a nonempty family of independent radicands has a nontrivial Galois group.
The Galois-group equivalence sends an automorphism to its multiplicative sign pattern.
The inverse of galoisGroupEquiv realizes a sign pattern ε as the automorphism sending each
generator rootᵢ to (-1)^(εᵢ) · rootᵢ.
Cardinality of the Galois group of a multiquadratic field. If no nonempty subset product
of the radicands d i is a square in K (and 2 ≠ 0 in K), then the multiquadratic field
M = K(rootᵢ : i) has |Gal(M/K)| = 2^|ι|. This is the cardinality reading of the explicit
isomorphism galoisGroupEquiv.
For square-class independent radicands, ∏ᵢ (X² - dᵢ) has Galois group (ℤ/2)ⁿ. The
splitting field of the defining polynomial contains a square root of every radicand, and it is the
multiquadratic field they generate, so galoisGroupEquiv applies to it. The isomorphism depends
on the choice of those square roots, which is why only its existence is stated.